Math  /  Calculus

QuestionA right triangle has legs of 33 inches and 44 inches whose sides are changing. The short leg is decreasing by 3in/sec3 \mathrm{in} / \mathrm{sec} and the long leg is growing at 8in/sec8 \mathrm{in} / \mathrm{sec}. What is the rate of change of the hypotenuse?

Studdy Solution

STEP 1

1. The triangle is a right triangle.
2. The legs of the triangle are initially 33 inches and 44 inches.
3. The short leg is decreasing at a rate of 3in/sec3 \, \text{in/sec}.
4. The long leg is increasing at a rate of 8in/sec8 \, \text{in/sec}.
5. We need to find the rate of change of the hypotenuse.

STEP 2

1. Use the Pythagorean theorem to express the hypotenuse in terms of the legs.
2. Differentiate the Pythagorean theorem with respect to time to find the rate of change of the hypotenuse.
3. Substitute the given rates of change of the legs into the differentiated equation to solve for the rate of change of the hypotenuse.

STEP 3

The Pythagorean theorem for a right triangle states that c2=a2+b2 c^2 = a^2 + b^2 , where c c is the hypotenuse, and a a and b b are the legs.
Initially, a=33 a = 33 inches and b=44 b = 44 inches.

STEP 4

Differentiate the equation c2=a2+b2 c^2 = a^2 + b^2 with respect to time t t .
Using implicit differentiation, we get: 2cdcdt=2adadt+2bdbdt 2c \frac{dc}{dt} = 2a \frac{da}{dt} + 2b \frac{db}{dt}
Simplify to: cdcdt=adadt+bdbdt c \frac{dc}{dt} = a \frac{da}{dt} + b \frac{db}{dt}

STEP 5

Substitute the given rates: dadt=3in/sec \frac{da}{dt} = -3 \, \text{in/sec} and dbdt=8in/sec \frac{db}{dt} = 8 \, \text{in/sec} .
Calculate the initial hypotenuse c c using c=332+442 c = \sqrt{33^2 + 44^2} .
c=1089+1936=3025=55inches c = \sqrt{1089 + 1936} = \sqrt{3025} = 55 \, \text{inches}
Substitute into the differentiated equation: 55dcdt=33(3)+44(8) 55 \frac{dc}{dt} = 33(-3) + 44(8)
Calculate: 55dcdt=99+352 55 \frac{dc}{dt} = -99 + 352
55dcdt=253 55 \frac{dc}{dt} = 253
Solve for dcdt \frac{dc}{dt} : dcdt=25355 \frac{dc}{dt} = \frac{253}{55}
dcdt4.6in/sec \frac{dc}{dt} \approx 4.6 \, \text{in/sec}
The rate of change of the hypotenuse is approximately:
4.6in/sec \boxed{4.6 \, \text{in/sec}}

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