Math  /  Data & Statistics

QuestionA standard die is rolled. Find the probability that the number rolled is less than 5. Express your answer as a fraction in lowest terms or a decimal rounded to the nearest millionth.
Answer

Studdy Solution

STEP 1

What is this asking? What are the chances of rolling a number smaller than 5 on a regular six-sided die? Watch out! Don't include 5 itself; we only want numbers *less* than 5!

STEP 2

1. List the possible outcomes
2. List the favorable outcomes
3. Calculate the probability

STEP 3

When we roll a standard die, the possible outcomes are the numbers from 1 to 6.
Let's write that down as a set SS: S={1,2,3,4,5,6}S = \{1, 2, 3, 4, 5, 6\} There are 6\bf{6} possible outcomes in total!

STEP 4

We're looking for the numbers *less* than 5.
From our set SS, these are 1, 2, 3, and 4.
Let's call this set of favorable outcomes EE: E={1,2,3,4}E = \{1, 2, 3, 4\} So, there are 4\bf{4} favorable outcomes.

STEP 5

The probability of an event is the number of favorable outcomes divided by the total number of possible outcomes.
In our case, the probability P(E)P(E) is: P(E)=Number of favorable outcomesTotal number of possible outcomesP(E) = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}

STEP 6

We know there are 4\bf{4} favorable outcomes (from the set EE) and 6\bf{6} total possible outcomes (from the set SS).
Let's plug those numbers into our formula: P(E)=46P(E) = \frac{4}{6}

STEP 7

Now, let's simplify the fraction.
Both the numerator and denominator are divisible by 2.
Dividing both by 2 gives us: P(E)=4÷26÷2=23P(E) = \frac{4 \div 2}{6 \div 2} = \frac{2}{3}

STEP 8

The probability of rolling a number less than 5 is 23\frac{2}{3}.

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