Solve a problem of your own!
Download the Studdy App!

Math

Math Snap

PROBLEM

If A={a,b,c}A=\{a, b, c\} and B={b,c,d}B=\{b, c, d\}, why is AB{a,b,c,b,c,d}A \cup B \neq \{a, b, c, b, c, d\}? Choose the correct answer:
A. AB={a,b,c,d}A \cup B=\{a, b, c, d\}; elements aren't repeated in sets.
B. AB={b,c}A \cup B=\{b, c\}.
C. AB=A \cup B=\varnothing.
D. The union has fewer elements than either set.

STEP 1

Assumptions1. A={a,b,c}A=\{a, b, c\} is a set. B={b,c,d}B=\{b, c, d\} is a set3. The union of two sets, denoted ABA \cup B, is the set of elements which are in AA, in BB, or in both AA and BB

STEP 2

The union of two sets is defined as the set of elements which are in either of the sets or in both. This means that if an element appears in both sets, it is not repeated in the union of the sets.
AB={xxA or xB}A \cup B = \{x x \in A \text{ or } x \in B\}

STEP 3

Now, let's find the union of the given sets AA and BB.
AB={a,b,c}{b,c,d}A \cup B = \{a, b, c\} \cup \{b, c, d\}

STEP 4

We can see that the elements bb and cc are in both sets. However, in the union of the sets, each element is listed only once.
AB={a,b,c,d}A \cup B = \{a, b, c, d\}

SOLUTION

So, it is not true that AB={a,b,c,b,c,d}A \cup B=\{a, b, c, b, c, d\} because in the union of two sets, elements are not repeated. Therefore, the correct answer isA. It is not true that AB={a,b,c,b,c,d}A \cup B=\{a, b, c, b, c, d\} because AB={a,b,c,d}A \cup B=\{a, b, c, d\}. Elements are not repeated in sets.

Was this helpful?
banner

Start understanding anything

Get started now for free.

OverviewParentsContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord