QuestionA student scored $25\%$ and failed by 60 marks, while another scored $45\%$ and passed by 10 marks. Find max marks: (a) 450 (b) 350 (c) 525 (d) None of these

Studdy Solution

STEP 1

Assumptions1. The student who secured25% of the maximum marks fails by60 marks. . Another candidate who secures45% of the maximum marks gets10 marks more than the passing marks.
3. We need to find the maximum number of marks.

STEP 2

Let's denote the maximum marks by $M$ . According to the problem, the student who secured25% of the maximum marks fails by60 marks. We can write this as an equation $0.25M +60 =$ where $$ is the passing marks.

STEP 3

According to the problem, another student who secures45% of the maximum marks gets10 marks more than the passing marks. We can write this as another equation $0.45M = +10$

STEP 4

Now we have a system of two equations. We can solve this system by substitution or elimination. Let's use substitution. We can express $from the first equation and substitute it into the second equation$ 0.45M =0.25M +60 +10$$

STEP 5

implify the equation by subtracting $0.25M$ from both sides $0.20M =70$

STEP 6

Now, solve for $M$ by dividing both sides of the equation by $0.20$ $M = \frac{70}{0.20}$

STEP 7

Calculate the value of $M$ $M = \frac{70}{0.20} =350$ So, the maximum number of marks is350.

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QuestionA student scored $25\%$ and failed by 60 marks, while another scored $45\%$ and passed by 10 marks. Find max marks: (a) 450 (b) 350 (c) 525 (d) None of these

Studdy Solution

STEP 1

Assumptions1. The student who secured25% of the maximum marks fails by60 marks. . Another candidate who secures45% of the maximum marks gets10 marks more than the passing marks.
3. We need to find the maximum number of marks.

STEP 2

Let's denote the maximum marks by $M$ . According to the problem, the student who secured25% of the maximum marks fails by60 marks. We can write this as an equation $0.25M +60 =$ where $$ is the passing marks.

STEP 3

According to the problem, another student who secures45% of the maximum marks gets10 marks more than the passing marks. We can write this as another equation $0.45M = +10$

STEP 4

Now we have a system of two equations. We can solve this system by substitution or elimination. Let's use substitution. We can express $from the first equation and substitute it into the second equation$ 0.45M =0.25M +60 +10$$

STEP 5

implify the equation by subtracting $0.25M$ from both sides $0.20M =70$

STEP 6

Now, solve for $M$ by dividing both sides of the equation by $0.20$ $M = \frac{70}{0.20}$

STEP 7

Calculate the value of $M$ $M = \frac{70}{0.20} =350$ So, the maximum number of marks is350.

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QuestionA student scored 25%25\%25% and failed by 60 marks, while another scored 45%45\%45% and passed by 10 marks. Find max marks: (a) 450 (b) 350 (c) 525 (d) None of these

Studdy Solution

STEP 1

Assumptions1. The student who secured25% of the maximum marks fails by60 marks. . Another candidate who secures45% of the maximum marks gets10 marks more than the passing marks.3. We need to find the maximum number of marks.

STEP 2

Let's denote the maximum marks by MMM. According to the problem, the student who secured25% of the maximum marks fails by60 marks. We can write this as an equation0.25M+60=0.25M +60 =0.25M+60=where $$ is the passing marks.

STEP 3

According to the problem, another student who secures45% of the maximum marks gets10 marks more than the passing marks. We can write this as another equation0.45M=+100.45M = +100.45M=+10

STEP 4

STEP 5

implify the equation by subtracting 0.25M0.25M0.25M from both sides0.20M=700.20M =700.20M=70

STEP 6

Now, solve for MMM by dividing both sides of the equation by 0.200.200.20M=700.20M = \frac{70}{0.20}M=0.2070​

STEP 7

Calculate the value of MMMM=700.20=350M = \frac{70}{0.20} =350M=0.2070​=350So, the maximum number of marks is350.

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Studdy solves anything!

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

QuestionA student scored $25\%$ and failed by 60 marks, while another scored $45\%$ and passed by 10 marks. Find max marks: (a) 450 (b) 350 (c) 525 (d) None of these

Assumptions1. The student who secured25% of the maximum marks fails by60 marks. . Another candidate who secures45% of the maximum marks gets10 marks more than the passing marks.
3. We need to find the maximum number of marks.

Let's denote the maximum marks by $M$ . According to the problem, the student who secured25% of the maximum marks fails by60 marks. We can write this as an equation $0.25M +60 =$ where $$ is the passing marks.

According to the problem, another student who secures45% of the maximum marks gets10 marks more than the passing marks. We can write this as another equation $0.45M = +10$

implify the equation by subtracting $0.25M$ from both sides $0.20M =70$

Now, solve for $M$ by dividing both sides of the equation by $0.20$ $M = \frac{70}{0.20}$

Calculate the value of $M$ $M = \frac{70}{0.20} =350$ So, the maximum number of marks is350.