Math  /  Data & Statistics

Questiontank of water was drained at a constant rate. The table shows the number of gallons of water left rained for two amounts of time. \begin{tabular}{|c|c|} \hline Draining Time (minutes) & Water in Tank (gallons) \\ \hline 10 & 450 \\ \hline 30 & 330 \\ \hline \end{tabular}
Part A What is the rate at which the water was drained from the tank? A 11 gallons of water per minute (B) 6 gallons of water per minute (C) 45 gallons of water per minute
D 120 gallons of water per minute

Studdy Solution

STEP 1

What is this asking? How fast is the water draining from the tank, in gallons per minute? Watch out! Make sure to calculate the *change* in water, not just the amount at a single time.

STEP 2

1. Calculate the change in water.
2. Calculate the change in time.
3. Calculate the rate of draining.

STEP 3

Alright, let's **start** by figuring out how much water was actually drained!
We began with 450450 gallons and ended up with 330330 gallons.
So, the change is 450330=120450 - 330 = \mathbf{120} gallons.
That's a whole lot of water!

STEP 4

Now, let's see how long it took for that water to drain.
We started at 1010 minutes and finished at 3030 minutes.
So, the time elapsed is 3010=2030 - 10 = \mathbf{20} minutes.

STEP 5

The **rate** is simply how much water drained divided by how long it took.
So, we have 120 gallons20 minutes\frac{120 \text{ gallons}}{20 \text{ minutes}}.

STEP 6

Let's simplify that fraction!
We can divide both the top and bottom by 2020, which gives us 12020=120÷2020÷20=61=6\frac{120}{20} = \frac{120 \div 20}{20 \div 20} = \frac{6}{1} = \mathbf{6} gallons per minute.
Boom!

STEP 7

The water drained at a rate of 6\mathbf{6} gallons per minute.
So the answer is B!

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