Question\begin{tabular}{|c|c|} \hline 4 & \begin{tabular}{l} A vehicle of mass 900 kg is travelling with a velocity of $20 \mathrm{~m} / \mathrm{s}$ . \\ What is the momentum of the vehicle? \\ A $45 \mathrm{kgm} / \mathrm{s}$ \\ B $450 \mathrm{kgm} / \mathrm{s}$ \\ C $18000 \mathrm{kgm} / \mathrm{s}$ \\ D $180000 \mathrm{kgm} / \mathrm{s}$ \end{tabular} \\ \hline 5 & \begin{tabular}{l} A bullet of mass 0.10 kg travels horizontally at a speed of $600 \mathrm{~m} / \mathrm{s}$ . It strikes a stationary wooden block of mass 1.90 kg resting on a frictionless, horizontal surface. \\ The bullet stays in the block. \\ What is the speed of the bullet and the block immediately after the impact? \\ A $30 \mathrm{~m} / \mathrm{s}$ \\ B $32 \mathrm{~m} / \mathrm{s}$ \\ C $60 \mathrm{~m} / \mathrm{s}$ \\ D $134 \mathrm{~m} / \mathrm{s}$ \end{tabular} \\ \hline 6 & \begin{tabular}{l} A moving body undergoes a change of momentum. \\ What is a unit for change of momentum? \\ A Nm \\ B $\mathrm{N} / \mathrm{m}$ \\ C Ns \\ D $\mathrm{N} / \mathrm{s}$ \end{tabular} \\ \hline 7 & \begin{tabular}{l} The diagram shows a uniform bridge, 4.0 m long and weighing 10000 N . \\ The bridge is pivoted at one end. A force at the other end gradually increases until the bridge begins to lift. \\ What is the lifting force as the bridge starts to move upwards? \\ A 2500 N \\ B 5000 N \\ C $\quad 10000 \mathrm{~N}$ \\ D 20000 N \end{tabular} \\ \hline 8 & \begin{tabular}{l} The diagram shows a wooden beam of weight 20 N . The centre of mass of the beam is labelled $M$ . \\ There is a pivot at one end of the beam. The beam is kept horizontal by an upward force, F. \\ What is the magnitude of $F$ ? \\ A $\quad 12 \mathrm{~N}$ \\ B 20 N \\ C 30 N \\ D 33 N \end{tabular} \\ \hline \end{tabular}

Studdy Solution

STEP 1

What is this asking? What's the momentum of a 900 kg vehicle zipping along at $20 \text{ m/s}$ ? Watch out! Don't mix up the units; momentum is measured in $\text{kg} \cdot \text{m/s}$ .

STEP 2

1. Recall the momentum formula
2. Plug and chug

STEP 3

Alright, let's define momentum!
Momentum ( $p$ ) is simply the product of an object's mass ( $m$ ) and its velocity ( $v$ ).
So, our magic formula is: $p = m \cdot v$

STEP 4

Now, let's plug in our values.
We know the mass ( $m = 900 \text{ kg}$ ) and the velocity ( $v = 20 \text{ m/s}$ ).
Substituting these into our momentum formula: $p = 900 \text{ kg} \cdot 20 \text{ m/s}$

STEP 5

Time to calculate! $p = 18000 \text{ kg} \cdot \text{m/s}$

STEP 6

So, the vehicle's momentum is $18000 \text{ kg} \cdot \text{m/s}$ , which matches option C!

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Studdy Solution

STEP 1

What is this asking? What's the momentum of a 900 kg vehicle zipping along at $20 \text{ m/s}$ ? Watch out! Don't mix up the units; momentum is measured in $\text{kg} \cdot \text{m/s}$ .

STEP 2

1. Recall the momentum formula
2. Plug and chug

STEP 3

Alright, let's define momentum!
Momentum ( $p$ ) is simply the product of an object's mass ( $m$ ) and its velocity ( $v$ ).
So, our magic formula is: $p = m \cdot v$

STEP 4

Now, let's plug in our values.
We know the mass ( $m = 900 \text{ kg}$ ) and the velocity ( $v = 20 \text{ m/s}$ ).
Substituting these into our momentum formula: $p = 900 \text{ kg} \cdot 20 \text{ m/s}$

STEP 5

Time to calculate! $p = 18000 \text{ kg} \cdot \text{m/s}$

STEP 6

So, the vehicle's momentum is $18000 \text{ kg} \cdot \text{m/s}$ , which matches option C!

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Studdy Solution

STEP 1

What is this asking? What's the momentum of a 900 kg vehicle zipping along at 20 m/s20 \text{ m/s}20 m/s? Watch out! Don't mix up the units; momentum is measured in kg⋅m/s\text{kg} \cdot \text{m/s}kg⋅m/s.

STEP 2

1. Recall the momentum formula2. Plug and chug

STEP 3

Alright, let's **define momentum**!Momentum (ppp) is simply the product of an object's mass (mmm) and its velocity (vvv).So, our magic formula is: p=m⋅vp = m \cdot vp=m⋅v

STEP 4

Now, let's **plug in** our values.We know the mass (m=900 kgm = 900 \text{ kg}m=900 kg) and the velocity (v=20 m/sv = 20 \text{ m/s}v=20 m/s).Substituting these into our momentum formula: p=900 kg⋅20 m/sp = 900 \text{ kg} \cdot 20 \text{ m/s}p=900 kg⋅20 m/s

STEP 5

Time to **calculate**! p=18000 kg⋅m/sp = 18000 \text{ kg} \cdot \text{m/s}p=18000 kg⋅m/s

STEP 6

So, the vehicle's momentum is 18000 kg⋅m/s18000 \text{ kg} \cdot \text{m/s}18000 kg⋅m/s, which matches option C!

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Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

What is this asking? What's the momentum of a 900 kg vehicle zipping along at $20 \text{ m/s}$ ? Watch out! Don't mix up the units; momentum is measured in $\text{kg} \cdot \text{m/s}$ .

1. Recall the momentum formula
2. Plug and chug

Alright, let's define momentum!
Momentum ( $p$ ) is simply the product of an object's mass ( $m$ ) and its velocity ( $v$ ).
So, our magic formula is: $p = m \cdot v$

Now, let's plug in our values.
We know the mass ( $m = 900 \text{ kg}$ ) and the velocity ( $v = 20 \text{ m/s}$ ).
Substituting these into our momentum formula: $p = 900 \text{ kg} \cdot 20 \text{ m/s}$

Time to calculate! $p = 18000 \text{ kg} \cdot \text{m/s}$

So, the vehicle's momentum is $18000 \text{ kg} \cdot \text{m/s}$ , which matches option C!