Math

QuestionFind BCB C given that AC=2x5A C=2 x-5, AB=12A B=12, and BC=x6B C=x-6.

Studdy Solution

STEP 1

Assumptions1. The length of segment ACAC is x5x-5 . The length of segment ABAB is 1212
3. The length of segment BCBC is x6x-6
4. ACAC is the sum of ABAB and BCBC because they are on the same line

STEP 2

First, we need to set up an equation based on the assumption that ACAC is the sum of ABAB and BCBC.AC=AB+BCAC = AB + BC

STEP 3

Now, plug in the given values for ACAC, ABAB, and BCBC to create the equation.
(2x5)=12+(x6)(2x-5) =12 + (x-6)

STEP 4

implify the right side of the equation.
(2x)=x+6(2x-) = x +6

STEP 5

Subtract xx from both sides of the equation to isolate xx on one side.
x5=x -5 =

STEP 6

Add 55 to both sides of the equation to solve for xx.
x=6+5x =6 +5

STEP 7

Calculate the value of xx.
x=11x =11

STEP 8

Now that we have the value of xx, we can find the length of BCBC by substituting xx into the given expression for BCBC.
BC=x6BC = x -6

STEP 9

Plug in the value of xx to calculate the length of BCBC.
BC=116BC =11 -6

STEP 10

Calculate the length of BCBC.
BC=5BC =5The length of BCBC is5 units.

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