Math

QuestionAccording to Le Châtelier's principle, a system at equilibrium will respond to a stress by shifting in the direction that'rellieves the stress. Chemical reactions can be displaced from their equilibrium positions not only by adding or removing reactants or products but also by changing the volume or temperature. Changes in volume affect the value of the reaction quotient, QQ, whereas temperature changes affect the value of the equilibrium constant, KK.
Part A
For the following systems at equilibrium A:2NOCl(g)2NO(g)+Cl2( g)\mathrm{A}: 2 \mathrm{NOCl}(\mathrm{g}) \rightleftharpoons 2 \mathrm{NO}(\mathrm{g})+\mathrm{Cl}_{2}(\mathrm{~g}) B: H2( g)+I2( g)2HI(g)\mathrm{H}_{2}(\mathrm{~g})+\mathrm{I}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{HI}(\mathrm{g}) classify these changes by their effect. Drag the appropriate items to their respective bins. View Available Hint(s) Reset Help
System A System A System B Increase container size
Decrease container size Increase container size
System B Decrease container size
Leftward shift No shift Rightward shift

Studdy Solution

STEP 1

1. We are considering the effect of volume changes on gaseous equilibrium systems.
2. Le Châtelier's principle applies to these systems.
3. The changes in volume affect the reaction quotient Q Q .

STEP 2

1. Analyze the effect of volume changes on System A.
2. Analyze the effect of volume changes on System B.
3. Classify the shifts for each system.

STEP 3

For System A: 2NOCl(g)2NO(g)+Cl2( g) 2 \mathrm{NOCl}(\mathrm{g}) \rightleftharpoons 2 \mathrm{NO}(\mathrm{g})+\mathrm{Cl}_{2}(\mathrm{~g})
- The reaction involves 2 moles of gas on the left and 3 moles of gas on the right. - Increasing the container size decreases pressure, favoring the side with more moles of gas (rightward shift). - Decreasing the container size increases pressure, favoring the side with fewer moles of gas (leftward shift).

STEP 4

For System B: H2( g)+I2( g)2HI(g) \mathrm{H}_{2}(\mathrm{~g})+\mathrm{I}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{HI}(\mathrm{g})
- The reaction involves 2 moles of gas on both sides. - Changes in volume do not affect the equilibrium position since the number of moles of gas is the same on both sides (no shift).

STEP 5

Classify the shifts:
- System A: - Increase container size: Rightward shift - Decrease container size: Leftward shift
- System B: - Increase container size: No shift - Decrease container size: No shift

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