Math  /  Numbers & Operations

QuestionAfter reading The Master of the Bow, Brenna signs up for archery lessons. At her first lesson, she sets up her target 5 feet away from her. After lots of practice, she now sets up her target 15 yards away. How many times farther away does Brenna set up her target now?

Studdy Solution

STEP 1

What is this asking? How much farther away is Brenna's target now compared to when she started? Watch out! The initial distance is in feet and the current distance is in yards, so we need to convert to the same units before comparing!

STEP 2

1. Convert units
2. Calculate the scaling factor

STEP 3

Alright, let's **convert** those yards to feet so we're comparing apples to apples!
Remember there are **3 feet** in every **yard**.
So, if Brenna's target is now 15 yards\text{15 yards} away, that's the same as 153=45 feet15 \cdot 3 = \text{45 feet}.
See how we **multiplied** by 3?
That's because we're scaling up from yards to feet!

STEP 4

Now, let's figure out how many times farther Brenna's target is now.
She started at 5 feet\text{5 feet} and now she's at 45 feet\text{45 feet}.
To find out how many times farther, we **divide** the **new distance** by the **initial distance**:
45 feet5 feet=9 \frac{\text{45 feet}}{\text{5 feet}} = 9

STEP 5

So, Brenna sets up her target **9 times** farther away now than when she started!
We divided to one the "feet" units, so our answer is just a number, which makes sense since we're looking for a scaling factor.

STEP 6

Brenna sets up her target **9 times** farther away now.

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