Math

QuestionFind P(B)P(B) given P(A)=0.4P(A)=0.4, P(A or B)=0.95P(A \text{ or } B)=0.95, and P(A and B)=0.3P(A \text{ and } B)=0.3. Round to two decimal places.

Studdy Solution

STEP 1

Assumptions1. The probability of event A, denoted by(A), is0.4. The probability of either event A or event B occurring, denoted by(A or B), is0.953. The probability of both event A and event B occurring, denoted by(A and B), is0.34. The probability of event B, denoted by(B), is what we need to find

STEP 2

We can use the formula for the probability of the union of two events to find(B). The formula is(A or B)=(A)+(B)(A and B)(A \text { or } B) =(A) +(B) -(A \text { and } B)

STEP 3

We can rearrange this formula to solve for(B):
(B)=(A or B)(A)+(A and B)(B) =(A \text { or } B) -(A) +(A \text { and } B)

STEP 4

Now, plug in the given values for(A or B),(A), and(A and B) to calculate(B).
(B)=0.950.4+0.3(B) =0.95 -0.4 +0.3

STEP 5

Calculate the probability of event B.
(B)=0.950.4+0.3=0.85(B) =0.95 -0.4 +0.3 =0.85The probability of event B, rounded to two decimal places, is0.85.

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