Math  /  Algebra

QuestionAnswer the following problems. Show your solutions.
1. If yy varies directly as xx. If y=216y=216 when x=9x=9, a. What is the constant of variation for the given situation? b. What is the equation of variation? c. What is yy when x=12x=12 ? d. What is xx when y=27y=\underline{27} ?
2. If m varies inversely as n . If m=144\mathrm{m}=144 when n=4\mathrm{n}=4, a. What is the constant of variation for the given situation? b. What is the equation of variation? c. What is the value of mm when nn is 9 ? d. What is the value of nn when mm is 12 ?
3. Suppose aa varies jointly with bb and cc. if a=336,b=7a=336, b=7 and cc is 2 . a. What is the constant of variation for the given situation? b. What is the equation of variation? c. What is the value of a when b=9\mathrm{b}=9 and c=3\mathrm{c}=3 ? d. What is the value of bb when a=720a=720 and c=6c=\underline{6} ? e. What is the value of cc when a=960a=960 and b=8b=8 ?
4. Suppose a varies directly as b and inversely as c . If a=12\mathrm{a}=12, when b=8\mathrm{b}=8 and c is 4 . a. What is the constant of variation for the given situation? b. What is the equation of variation? c. What is the value of aa when b=9b=9 and c=3c=3 ? d. What is the value of bb when a=24a=24 and c=5c=5 ? e. What is the value of cc when a=45a=45 and b=15b=15 ?
5. If mm varies inversely as g and m=30\mathrm{m}=30 when g=7\mathrm{g}=7, a. What is the constant of variation for the given situation? b. What is the equation of variation? c. What is m when g is 21 ? d. What is g when m is 15 ?

Studdy Solution

STEP 1

1. We are dealing with problems involving direct, inverse, and joint variation.
2. The problems require finding constants of variation, equations of variation, and solving for unknown variables.

STEP 2

1. Solve Problem 1: Direct Variation
2. Solve Problem 2: Inverse Variation
3. Solve Problem 3: Joint Variation
4. Solve Problem 4: Direct and Inverse Variation
5. Solve Problem 5: Inverse Variation

STEP 3

Solve Problem 1: Direct Variation
a. Determine the constant of variation k k .
Since y y varies directly as x x , we have y=kx y = kx .
Given y=216 y = 216 when x=9 x = 9 , substitute these values into the equation:
216=k×9 216 = k \times 9
Solve for k k :
k=2169=24 k = \frac{216}{9} = 24

STEP 4

b. Write the equation of variation.
The equation is y=24x y = 24x .

STEP 5

c. Find y y when x=12 x = 12 .
Substitute x=12 x = 12 into the equation y=24x y = 24x :
y=24×12=288 y = 24 \times 12 = 288

STEP 6

d. Find x x when y=27 y = 27 .
Substitute y=27 y = 27 into the equation y=24x y = 24x :
27=24x 27 = 24x
Solve for x x :
x=2724=98 x = \frac{27}{24} = \frac{9}{8}

STEP 7

Solve Problem 2: Inverse Variation
a. Determine the constant of variation k k .
Since m m varies inversely as n n , we have m=kn m = \frac{k}{n} .
Given m=144 m = 144 when n=4 n = 4 , substitute these values into the equation:
144=k4 144 = \frac{k}{4}
Solve for k k :
k=144×4=576 k = 144 \times 4 = 576

STEP 8

b. Write the equation of variation.
The equation is m=576n m = \frac{576}{n} .

STEP 9

c. Find m m when n=9 n = 9 .
Substitute n=9 n = 9 into the equation m=576n m = \frac{576}{n} :
m=5769=64 m = \frac{576}{9} = 64

STEP 10

d. Find n n when m=12 m = 12 .
Substitute m=12 m = 12 into the equation m=576n m = \frac{576}{n} :
12=576n 12 = \frac{576}{n}
Solve for n n :
n=57612=48 n = \frac{576}{12} = 48

STEP 11

Solve Problem 3: Joint Variation
a. Determine the constant of variation k k .
Since a a varies jointly with b b and c c , we have a=kbc a = kbc .
Given a=336 a = 336 , b=7 b = 7 , and c=2 c = 2 , substitute these values into the equation:
336=k×7×2 336 = k \times 7 \times 2
Solve for k k :
k=33614=24 k = \frac{336}{14} = 24

STEP 12

b. Write the equation of variation.
The equation is a=24bc a = 24bc .

STEP 13

c. Find a a when b=9 b = 9 and c=3 c = 3 .
Substitute b=9 b = 9 and c=3 c = 3 into the equation a=24bc a = 24bc :
a=24×9×3=648 a = 24 \times 9 \times 3 = 648

STEP 14

d. Find b b when a=720 a = 720 and c=6 c = 6 .
Substitute a=720 a = 720 and c=6 c = 6 into the equation a=24bc a = 24bc :
720=24b×6 720 = 24b \times 6
Solve for b b :
b=720144=5 b = \frac{720}{144} = 5

STEP 15

e. Find c c when a=960 a = 960 and b=8 b = 8 .
Substitute a=960 a = 960 and b=8 b = 8 into the equation a=24bc a = 24bc :
960=24×8×c 960 = 24 \times 8 \times c
Solve for c c :
c=960192=5 c = \frac{960}{192} = 5

STEP 16

Solve Problem 4: Direct and Inverse Variation
a. Determine the constant of variation k k .
Since a a varies directly as b b and inversely as c c , we have a=kbc a = k \frac{b}{c} .
Given a=12 a = 12 , b=8 b = 8 , and c=4 c = 4 , substitute these values into the equation:
12=k84 12 = k \frac{8}{4}
Solve for k k :
k=12×48=6 k = \frac{12 \times 4}{8} = 6

STEP 17

b. Write the equation of variation.
The equation is a=6bc a = 6 \frac{b}{c} .

STEP 18

c. Find a a when b=9 b = 9 and c=3 c = 3 .
Substitute b=9 b = 9 and c=3 c = 3 into the equation a=6bc a = 6 \frac{b}{c} :
a=693=18 a = 6 \frac{9}{3} = 18

STEP 19

d. Find b b when a=24 a = 24 and c=5 c = 5 .
Substitute a=24 a = 24 and c=5 c = 5 into the equation a=6bc a = 6 \frac{b}{c} :
24=6b5 24 = 6 \frac{b}{5}
Solve for b b :
b=24×56=20 b = \frac{24 \times 5}{6} = 20

STEP 20

e. Find c c when a=45 a = 45 and b=15 b = 15 .
Substitute a=45 a = 45 and b=15 b = 15 into the equation a=6bc a = 6 \frac{b}{c} :
45=615c 45 = 6 \frac{15}{c}
Solve for c c :
c=6×1545=2 c = \frac{6 \times 15}{45} = 2

STEP 21

Solve Problem 5: Inverse Variation
a. Determine the constant of variation k k .
Since m m varies inversely as g g , we have m=kg m = \frac{k}{g} .
Given m=30 m = 30 when g=7 g = 7 , substitute these values into the equation:
30=k7 30 = \frac{k}{7}
Solve for k k :
k=30×7=210 k = 30 \times 7 = 210

STEP 22

b. Write the equation of variation.
The equation is m=210g m = \frac{210}{g} .

STEP 23

c. Find m m when g=21 g = 21 .
Substitute g=21 g = 21 into the equation m=210g m = \frac{210}{g} :
m=21021=10 m = \frac{210}{21} = 10

STEP 24

d. Find g g when m=15 m = 15 .
Substitute m=15 m = 15 into the equation m=210g m = \frac{210}{g} :
15=210g 15 = \frac{210}{g}
Solve for g g :
g=21015=14 g = \frac{210}{15} = 14

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