QuestionAt 1:00, both towns had the same temperature. By 3:00, Jonestown's temp dropped 18 degrees and Cooperville's dropped 8 degrees. a. Model Jonestown's temp change with an equation. b. Model Cooperville's temp change with an equation. c. Which town was colder at 3:00?
Studdy Solution
STEP 1
Assumptions1. The temperature in Jonestown and Cooperville was the same at100.
. By00, the temperature in Jonestown dropped10 degrees, and the temperature in Cooperville dropped6 degrees.
3. By300, the temperature in Jonestown dropped8 more degrees, and the temperature in Cooperville dropped more degrees.
STEP 2
Let's denote the initial temperature at100 in both cities as. The change in temperature in Jonestown by200 is -10 degrees, and by00 it is -8 degrees. So, the total change in temperature in Jonestown since100 is -10 -8 = -18 degrees.
STEP 3
Write an equation that models the change to the temperature in Jonestown since100.
STEP 4
Now, let's consider the change in temperature in Cooperville. By200, the temperature dropped by6 degrees, and by300, it dropped by2 more degrees. So, the total change in temperature in Cooperville since100 is -6 -2 = -8 degrees.
STEP 5
Write an equation that models the change to the temperature in Cooperville since100.
STEP 6
Now, we need to find out where it was colder at300, in Jonestown or Cooperville. We can do this by comparing the temperatures in both cities at300.
STEP 7
Since the initial temperatures in both cities were the same, and the temperature dropped more in Jonestown than in Cooperville, it was colder in Jonestown at300.
So, at300, it was colder in Jonestown than in Cooperville.
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