Math  /  Algebra

Questionb235b+300=0b^{2}-35 b+300=0

Studdy Solution

STEP 1

1. The equation b235b+300=0b^2 - 35b + 300 = 0 is a quadratic equation in the variable bb.
2. The solutions to the quadratic equation can be found using the quadratic formula, factoring, or completing the square.
3. The quadratic formula is given by b=B±B24AC2Ab = \frac{-B \pm \sqrt{B^2 - 4AC}}{2A}, where AA, BB, and CC are the coefficients of the terms b2b^2, bb, and the constant term, respectively.

STEP 2

1. Identify the coefficients AA, BB, and CC in the quadratic equation.
2. Apply the quadratic formula to find the solutions for bb.
3. Simplify the solutions to obtain the final values for bb.

STEP 3

Identify the coefficients AA, BB, and CC in the quadratic equation b235b+300=0b^2 - 35b + 300 = 0.
Here, A=1A = 1, B=35B = -35, and C=300C = 300.

STEP 4

Apply the quadratic formula b=B±B24AC2Ab = \frac{-B \pm \sqrt{B^2 - 4AC}}{2A} using the identified coefficients.
b=(35)±(35)24130021 b = \frac{-(-35) \pm \sqrt{(-35)^2 - 4 \cdot 1 \cdot 300}}{2 \cdot 1}

STEP 5

Simplify the expression inside the square root.
b=35±122512002 b = \frac{35 \pm \sqrt{1225 - 1200}}{2} b=35±252 b = \frac{35 \pm \sqrt{25}}{2}

STEP 6

Simplify the square root and then the entire expression.
b=35±52 b = \frac{35 \pm 5}{2}

STEP 7

Calculate the two possible solutions for bb.
b1=35+52=402=20 b_1 = \frac{35 + 5}{2} = \frac{40}{2} = 20
b2=3552=302=15 b_2 = \frac{35 - 5}{2} = \frac{30}{2} = 15

STEP 8

The solutions to the quadratic equation b235b+300=0b^2 - 35b + 300 = 0 are b=20b = 20 and b=15b = 15.
Therefore, the values for bb are b=20b = 20 and b=15b = 15.

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