Math

QuestionCaden hits a golf ball at 2.0 m/s2.0 \mathrm{~m/s}, slowing at 0.5 m/s2-0.5 \mathrm{~m/s}^2. What's its velocity after 2.0 s2.0 \mathrm{~s}?

Studdy Solution

STEP 1

Assumptions1. The initial velocity of the golf ball is .0m/s.0 \, \mathrm{m/s} . The acceleration (rate of slowing down) is -0.5 \, \mathrm{m/s^}
3. The time interval is .0s.0 \, \mathrm{s}

STEP 2

We will use the formula for velocity in terms of initial velocity, acceleration, and time.
v=u+atv = u + atwhere- vv is the final velocity, - uu is the initial velocity, - aa is the acceleration, and- tt is the time.

STEP 3

Now, plug in the given values for the initial velocity, acceleration, and time into the formula.
v=2.0m/s+(0.5m/s2)(2.0s)v =2.0 \, \mathrm{m/s} + (-0.5 \, \mathrm{m/s^2})(2.0 \, \mathrm{s})

STEP 4

Perform the multiplication in the equation.
v=2.0m/s+(1.0m/s)v =2.0 \, \mathrm{m/s} + (-1.0 \, \mathrm{m/s})

STEP 5

Perform the addition in the equation.
v=1.0m/sv =1.0 \, \mathrm{m/s}So, the velocity of the golf ball after 2.0s2.0 \, \mathrm{s} is 1.0m/s1.0 \, \mathrm{m/s}.

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