Math

QuestionCalcola perimetro e area di un triangolo rettangolo con cateti di 10 cm10 \mathrm{~cm} e 24 cm24 \mathrm{~cm}.

Studdy Solution

STEP 1

Assumptions1. We have a right triangle. . The lengths of the two legs (cateti) are given as10 cm and24 cm.
3. We need to find the perimeter and the area of the triangle.

STEP 2

First, we need to find the length of the hypotenuse (ipotenusa) using the Pythagorean theorem.
potenusa=Cateto12+Cateto22potenusa = \sqrt{Cateto1^2 + Cateto2^2}

STEP 3

Now, plug in the given values for the lengths of the two legs to calculate the length of the hypotenuse.
potenusa=102+242potenusa = \sqrt{10^2 +24^2}

STEP 4

Calculate the length of the hypotenuse.
potenusa=102+242=100+576=676=26 cmpotenusa = \sqrt{10^2 +24^2} = \sqrt{100 +576} = \sqrt{676} =26 \mathrm{~cm}

STEP 5

Now that we have the length of the hypotenuse, we can find the perimeter of the triangle. The perimeter is the sum of the lengths of all sides.
Perimetro=Cateto1+Cateto2+IpotenusaPerimetro = Cateto1 + Cateto2 + Ipotenusa

STEP 6

Plug in the values for the lengths of the two legs and the hypotenuse to calculate the perimeter.
Perimetro=10 cm+24 cm+26 cmPerimetro =10 \mathrm{~cm} +24 \mathrm{~cm} +26 \mathrm{~cm}

STEP 7

Calculate the perimeter of the triangle.
Perimetro=10 cm+24 cm+26 cm=60 cmPerimetro =10 \mathrm{~cm} +24 \mathrm{~cm} +26 \mathrm{~cm} =60 \mathrm{~cm}

STEP 8

Now that we have the perimeter, we can find the area of the triangle. The area of a right triangle is given by the formulaArea=12×Cateto1×Cateto2Area = \frac{1}{2} \times Cateto1 \times Cateto2

STEP 9

Plug in the values for the lengths of the two legs to calculate the area.
Area=2× cm×24 cmArea = \frac{}{2} \times \mathrm{~cm} \times24 \mathrm{~cm}

STEP 10

Calculate the area of the triangle.
Area=2×10 cm×24 cm=120 cm2Area = \frac{}{2} \times10 \mathrm{~cm} \times24 \mathrm{~cm} =120 \mathrm{~cm}^2The perimeter of the triangle is60 cm and the area is120 cm².

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