QuestionCalculate the moles of oxygen needed for 1.8 mol of carbon dioxide from burning octane .
Studdy Solution
STEP 1
Question: What is the balanced chemical equation for the reaction of octane with oxygen?
A) C8H18 + O2 → CO2 + H2O
B) C8H18 + 12.5O2 → 8CO2 + 9H2O
C) C8H18 + 2O2 → 8CO2 + 9H2O
D) C8H18 + O2 → 8CO2 + 18H2O
Answer: B) C8H18 + 12.5O2 → 8CO2 + 9H2O
STEP 2
Question: What is the mole ratio between carbon dioxide and oxygen in the balanced chemical equation?
A) 8:12.5
B) 2:1
C) 1:1
D) 12.5:8
Answer: A) 8:12.5
STEP 3
Question: How would you express the given problem as a ratio using the mole ratio from the balanced chemical equation?
A) 8/12.5 = x/1.8
B) 8/1.8 = x/12.5
C) 1.8/8 = x/12.5
D) 12.5/8 = 1.8/x
Answer: A) 8/12.5 = x/1.8
STEP 4
Question: Solve for x in the equation 8x = 1.8 * 12.5.
A) x = 1.8 * 12.5 / 8
B) x = 8 / 1.8 * 12.5
C) x = 8 * 12.5 / 1.8
D) x = 1.8 / 8 * 12.5
Answer: A) x = 1.8 * 12.5 / 8
STEP 5
Question: If the calculated value of x is 2.8125, what would be the value of x rounded to the correct number of significant digits?
A) 2.81
B) 2.812
C) 2.8
D) 3
Answer: C) 2.8
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