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QuestionProve that for △ABC\triangle ABC with external angle ∠ACD\angle ACD, m∠ACD=m∠B+m∠Am \angle ACD = m \angle B + m \angle A.

Studdy Solution

STEP 1

Assumptions1. We are given a triangle △ABC\triangle A B C with an external angle ∠ACD\angle A C D. . We need to prove that m∠ACD=m∠B+m∠Am \angle A C D = m \angle B + m \angle A.
3. The given proof table provides the statements and reasons used in the proof.
4. We need to find the reason for the first statement, "Triangle △ABC\triangle A B C with external angle ∠ACD\angle A C D".

STEP 2

The first statement is given as a fact, so the reason for this statement is "Given".Reason for △ABC with external angle, ∠ACD="Given"\text{Reason for } \triangle A B C \text{ with external angle, } \angle A C D = \text{"Given"}

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