QuestionSolve the equation step by step and fill in missing terms: $4(7d+2)+6=14$ . Simplify fractions where needed.

Studdy Solution

STEP 1

Assumptions1. The given equation is $4(7d+)+6 =14$ . The goal is to solve for the variable $d$
3. The equation is a linear equation4. The operations of addition, subtraction, multiplication, and division are allowed

STEP 2

The given equation is $4(7d+2)+6 =14$ . First, distribute the4 to both terms inside the parentheses.
$4(7d+2)+6 =14$ $28d +8 +6 =14$

STEP 3

Combine like terms on the left side of the equation.
$28d +8 +6 =28d +14 =14$ So, the missing term in the third line of the equation is14.

STEP 4

Subtract14 from both sides of the equation to isolate the term with the variable $d$ .
$28d +14 -14 =14 -14$ $28d =0$

STEP 5

Finally, divide both sides of the equation by28 to solve for $d$ .
$d = \frac{0}{28}$ So, the missing term in the last line of the equation is0.

STEP 6

implify the fraction.
$d =0$ Therefore, the solution to the equation is $d =0$ .

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QuestionSolve the equation step by step and fill in missing terms: $4(7d+2)+6=14$ . Simplify fractions where needed.

Studdy Solution

STEP 1

Assumptions1. The given equation is $4(7d+)+6 =14$ . The goal is to solve for the variable $d$
3. The equation is a linear equation4. The operations of addition, subtraction, multiplication, and division are allowed

STEP 2

The given equation is $4(7d+2)+6 =14$ . First, distribute the4 to both terms inside the parentheses.
$4(7d+2)+6 =14$ $28d +8 +6 =14$

STEP 3

Combine like terms on the left side of the equation.
$28d +8 +6 =28d +14 =14$ So, the missing term in the third line of the equation is14.

STEP 4

Subtract14 from both sides of the equation to isolate the term with the variable $d$ .
$28d +14 -14 =14 -14$ $28d =0$

STEP 5

Finally, divide both sides of the equation by28 to solve for $d$ .
$d = \frac{0}{28}$ So, the missing term in the last line of the equation is0.

STEP 6

implify the fraction.
$d =0$ Therefore, the solution to the equation is $d =0$ .

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QuestionSolve the equation step by step and fill in missing terms: 4(7d+2)+6=144(7d+2)+6=144(7d+2)+6=14. Simplify fractions where needed.

Studdy Solution

STEP 1

Assumptions1. The given equation is 4(7d+)+6=144(7d+)+6 =144(7d+)+6=14 . The goal is to solve for the variable ddd3. The equation is a linear equation4. The operations of addition, subtraction, multiplication, and division are allowed

STEP 2

The given equation is 4(7d+2)+6=144(7d+2)+6 =144(7d+2)+6=14. First, distribute the4 to both terms inside the parentheses.4(7d+2)+6=144(7d+2)+6 =144(7d+2)+6=1428d+8+6=1428d +8 +6 =1428d+8+6=14

STEP 3

Combine like terms on the left side of the equation.28d+8+6=28d+14=1428d +8 +6 =28d +14 =1428d+8+6=28d+14=14So, the missing term in the third line of the equation is14.

STEP 4

Subtract14 from both sides of the equation to isolate the term with the variable ddd.28d+14−14=14−1428d +14 -14 =14 -1428d+14−14=14−1428d=028d =028d=0

STEP 5

Finally, divide both sides of the equation by28 to solve for ddd.d=028d = \frac{0}{28}d=280​So, the missing term in the last line of the equation is0.

STEP 6

implify the fraction.d=0d =0d=0Therefore, the solution to the equation is d=0d =0d=0.

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QuestionSolve the equation step by step and fill in missing terms: $4(7d+2)+6=14$ . Simplify fractions where needed.

Assumptions1. The given equation is $4(7d+)+6 =14$ . The goal is to solve for the variable $d$
3. The equation is a linear equation4. The operations of addition, subtraction, multiplication, and division are allowed

The given equation is $4(7d+2)+6 =14$ . First, distribute the4 to both terms inside the parentheses.
$4(7d+2)+6 =14$ $28d +8 +6 =14$

Combine like terms on the left side of the equation.
$28d +8 +6 =28d +14 =14$ So, the missing term in the third line of the equation is14.

Subtract14 from both sides of the equation to isolate the term with the variable $d$ .
$28d +14 -14 =14 -14$ $28d =0$

Finally, divide both sides of the equation by28 to solve for $d$ .
$d = \frac{0}{28}$ So, the missing term in the last line of the equation is0.

implify the fraction.
$d =0$ Therefore, the solution to the equation is $d =0$ .