Math / Algebra

QuestionComplete the table for the given rule. Rule: $y = x + 3$

Studdy Solution

STEP 1

What is this asking? Given the rule $y = x + 3$ , we need to find the missing $x$ values in the table for the given $y$ values. Watch out! Don't mix up $x$ and $y$ !
Remember, we're solving for $x$ , not $y$ .

STEP 2

1. Solve for x when y = 4
2. Solve for x when y = 8
3. Solve for x when y = 5

STEP 3

Alright, let's start with our given rule: $y = x + 3$ .
We know that in this case, our y-value is 4.
Let's plug it in!

STEP 4

So, we have $4 = x + 3$ .
Now, we want to isolate that mischievous $x$ , so we'll subtract 3 from both sides of the equation.
Remember, what we do to one side, we must do to the other to keep things balanced!

STEP 5

$4 - 3 = x + 3 - 3$ $1 = x$ Boom! We found our first x-value: $x = 1$ when $y = 4$ .

STEP 6

Back to our trusty rule: $y = x + 3$ .
This time, our y-value is 8.
Let's substitute that in.

STEP 7

We get $8 = x + 3$ .
To get x by itself, we'll subtract 3 from both sides.

STEP 8

$8 - 3 = x + 3 - 3$ $5 = x$ Awesome! Our second x-value is $x = 5$ when $y = 8$ .

STEP 9

One more time with feeling!
Our rule is $y = x + 3$ , and our y-value is 5.
Let's plug it in!

STEP 10

So, $5 = x + 3$ .
We'll subtract 3 from both sides to isolate x.

STEP 11

$5 - 3 = x + 3 - 3$ $2 = x$ Fantastic! Our final x-value is $x = 2$ when $y = 5$ .

STEP 12

When $y = 4$ , $x = 1$ . When $y = 8$ , $x = 5$ . When $y = 5$ , $x = 2$ .

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QuestionComplete the table for the given rule. Rule: $y = x + 3$

Studdy Solution

STEP 1

What is this asking? Given the rule $y = x + 3$ , we need to find the missing $x$ values in the table for the given $y$ values. Watch out! Don't mix up $x$ and $y$ !
Remember, we're solving for $x$ , not $y$ .

STEP 2

1. Solve for x when y = 4
2. Solve for x when y = 8
3. Solve for x when y = 5

STEP 3

Alright, let's start with our given rule: $y = x + 3$ .
We know that in this case, our y-value is 4.
Let's plug it in!

STEP 4

So, we have $4 = x + 3$ .
Now, we want to isolate that mischievous $x$ , so we'll subtract 3 from both sides of the equation.
Remember, what we do to one side, we must do to the other to keep things balanced!

STEP 5

$4 - 3 = x + 3 - 3$ $1 = x$ Boom! We found our first x-value: $x = 1$ when $y = 4$ .

STEP 6

Back to our trusty rule: $y = x + 3$ .
This time, our y-value is 8.
Let's substitute that in.

STEP 7

We get $8 = x + 3$ .
To get x by itself, we'll subtract 3 from both sides.

STEP 8

$8 - 3 = x + 3 - 3$ $5 = x$ Awesome! Our second x-value is $x = 5$ when $y = 8$ .

STEP 9

One more time with feeling!
Our rule is $y = x + 3$ , and our y-value is 5.
Let's plug it in!

STEP 10

So, $5 = x + 3$ .
We'll subtract 3 from both sides to isolate x.

STEP 11

$5 - 3 = x + 3 - 3$ $2 = x$ Fantastic! Our final x-value is $x = 2$ when $y = 5$ .

STEP 12

When $y = 4$ , $x = 1$ . When $y = 8$ , $x = 5$ . When $y = 5$ , $x = 2$ .

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QuestionComplete the table for the given rule. Rule: y=x+3y = x + 3y=x+3

Studdy Solution

STEP 1

What is this asking? Given the rule y=x+3y = x + 3y=x+3, we need to find the missing xxx values in the table for the given yyy values. Watch out! Don't mix up xxx and yyy!Remember, we're solving for xxx, not yyy.

STEP 2

1. Solve for x when y = 42. Solve for x when y = 83. Solve for x when y = 5

STEP 3

Alright, let's **start** with our given rule: y=x+3y = x + 3y=x+3.We know that in this case, our **y-value** is **4**.Let's **plug it in**!

STEP 4

So, we have 4=x+34 = x + 34=x+3.Now, we want to **isolate** that mischievous xxx, so we'll **subtract 3** from *both* sides of the equation.Remember, what we do to one side, we *must* do to the other to keep things balanced!

STEP 5

4−3=x+3−34 - 3 = x + 3 - 34−3=x+3−3 1=x1 = x1=x Boom! We found our **first x-value**: x=1x = 1x=1 when y=4y = 4y=4.

STEP 6

Back to our trusty rule: y=x+3y = x + 3y=x+3.This time, our **y-value** is **8**.Let's **substitute** that in.

STEP 7

We get 8=x+38 = x + 38=x+3.To **get x by itself**, we'll **subtract 3** from both sides.

STEP 8

8−3=x+3−38 - 3 = x + 3 - 38−3=x+3−3 5=x5 = x5=x Awesome! Our **second x-value** is x=5x = 5x=5 when y=8y = 8y=8.

STEP 9

One more time with feeling!Our rule is y=x+3y = x + 3y=x+3, and our **y-value** is **5**.Let's **plug it in**!

STEP 10

So, 5=x+35 = x + 35=x+3.We'll **subtract 3** from both sides to **isolate x**.

STEP 11

5−3=x+3−35 - 3 = x + 3 - 35−3=x+3−3 2=x2 = x2=x Fantastic! Our **final x-value** is x=2x = 2x=2 when y=5y = 5y=5.

STEP 12

When y=4y = 4y=4, x=1x = 1x=1. When y=8y = 8y=8, x=5x = 5x=5. When y=5y = 5y=5, x=2x = 2x=2.

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Studdy solves anything!

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QuestionComplete the table for the given rule. Rule: $y = x + 3$

What is this asking? Given the rule $y = x + 3$ , we need to find the missing $x$ values in the table for the given $y$ values. Watch out! Don't mix up $x$ and $y$ !
Remember, we're solving for $x$ , not $y$ .

1. Solve for x when y = 4
2. Solve for x when y = 8
3. Solve for x when y = 5

Alright, let's start with our given rule: $y = x + 3$ .
We know that in this case, our y-value is 4.
Let's plug it in!

So, we have $4 = x + 3$ .
Now, we want to isolate that mischievous $x$ , so we'll subtract 3 from both sides of the equation.
Remember, what we do to one side, we must do to the other to keep things balanced!

$4 - 3 = x + 3 - 3$ $1 = x$ Boom! We found our first x-value: $x = 1$ when $y = 4$ .

Back to our trusty rule: $y = x + 3$ .
This time, our y-value is 8.
Let's substitute that in.

We get $8 = x + 3$ .
To get x by itself, we'll subtract 3 from both sides.

$8 - 3 = x + 3 - 3$ $5 = x$ Awesome! Our second x-value is $x = 5$ when $y = 8$ .

One more time with feeling!
Our rule is $y = x + 3$ , and our y-value is 5.
Let's plug it in!

So, $5 = x + 3$ .
We'll subtract 3 from both sides to isolate x.

$5 - 3 = x + 3 - 3$ $2 = x$ Fantastic! Our final x-value is $x = 2$ when $y = 5$ .

When $y = 4$ , $x = 1$ . When $y = 8$ , $x = 5$ . When $y = 5$ , $x = 2$ .