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Math  /  Algebra

QuestionComplete the table. \begin{tabular}{|c|c|} \hline \multicolumn{2}{|c|}{f(x)=x+1f(x)=x+1} \\ \hlinexx & f(x)f(x) \\ \hline 1 & □\square \\ \hline 2 & □\square \\ \hline 3 & □\square \\ \hline 4 & □\square \\ \hline \end{tabular}

Studdy Solution

STEP 1

What is this asking? We need to find the output of the function f(x)=x+1f(x) = x + 1 for the input values x=1,2,3,x = 1, 2, 3, and 44. Watch out! Make sure to substitute the correct xx value into the function each time!

STEP 2

1. Substitute and Solve for f(1)f(1)
2. Substitute and Solve for f(2)f(2)
3. Substitute and Solve for f(3)f(3)
4. Substitute and Solve for f(4)f(4)

STEP 3

Alright, let's **kick things off** with x=1x = 1!
We've got our function f(x)=x+1f(x) = x + 1.

STEP 4

We'll **substitute** x=1x = 1 into the function: f(1)=1+1f(1) = 1 + 1.

STEP 5

Now, let's **calculate** the result: f(1)=2f(1) = 2.
Awesome!

STEP 6

Next up, x=2x = 2!
Remember, our function is f(x)=x+1f(x) = x + 1.

STEP 7

Let's **substitute** x=2x = 2 into the function: f(2)=2+1f(2) = 2 + 1.

STEP 8

**Calculate** the result: f(2)=3f(2) = 3.
Fantastic!

STEP 9

Now for x=3x = 3.
Our function is still f(x)=x+1f(x) = x + 1.

STEP 10

**Substitute** x=3x = 3 into the function: f(3)=3+1f(3) = 3 + 1.

STEP 11

**Calculate** the result: f(3)=4f(3) = 4.
Keep it going!

STEP 12

Last but not least, x=4x = 4!
Our function remains f(x)=x+1f(x) = x + 1.

STEP 13

**Substitute** x=4x = 4 into the function: f(4)=4+1f(4) = 4 + 1.

STEP 14

**Calculate** the result: f(4)=5f(4) = 5.
We did it!

STEP 15

Here's our completed table:
xf(x)12233445\begin{array}{cc} x & f(x) \\ 1 & 2 \\ 2 & 3 \\ 3 & 4 \\ 4 & 5 \\ \end{array}

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