Math

Question Solve the quadratic equation 8x2=7x58 x^{2} = 7 x - 5 and compute its discriminant.

Studdy Solution

STEP 1

Assumptions
1. The given equation is 8x2=7x58x^2 = 7x - 5.
2. The standard form of a quadratic equation is ax2+bx+c=0ax^2 + bx + c = 0.
3. The discriminant of a quadratic equation ax2+bx+c=0ax^2 + bx + c = 0 is given by D=b24acD = b^2 - 4ac.
4. We need to rewrite the given equation in the standard form to compute the discriminant.

STEP 2

First, we need to rewrite the given equation in standard form by bringing all terms to one side of the equation.
8x27x+5=08x^2 - 7x + 5 = 0

STEP 3

Identify the coefficients aa, bb, and cc from the standard form of the quadratic equation.
In our equation, a=8a = 8, b=7b = -7, and c=5c = 5.

STEP 4

Now, we will use the formula for the discriminant D=b24acD = b^2 - 4ac to compute the discriminant of the given quadratic equation.

STEP 5

Substitute the values of aa, bb, and cc into the discriminant formula.
D=(7)24(8)(5)D = (-7)^2 - 4(8)(5)

STEP 6

Calculate the square of bb.
(7)2=49(-7)^2 = 49

STEP 7

Calculate the product of 44, aa, and cc.
4(8)(5)=1604(8)(5) = 160

STEP 8

Subtract the product of 4ac4ac from b2b^2 to find the discriminant.
D=49160D = 49 - 160

STEP 9

Compute the discriminant.
D=49160=111D = 49 - 160 = -111
The discriminant of the quadratic equation 8x2=7x58x^2 = 7x - 5 is 111-111.

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