Math  /  Geometry

QuestionConsider parallelogram GHJK below.
Note that GHJKG H J K has vertices G(4,2),H(1,3),J(4,4)G(-4,2), H(1,3), J(4,-4), and K(1,5)K(-1,-5). Answer the following to determine if the parallelogram is a rectangle, rhombus, square, or none of these. (a) Find the slope of HJ\overline{H J} and the slope of a side adjacent to HJ\overline{H J}.
Slope of HJ\overline{H J} : \square
Slope of side adjacent to HJ\overline{H J} : \square (b) Find the length of HJ\overline{H J} and the length of a side adjacent to HJ\overline{H J}. Give exact answers (not decimal approximations).
Length of HJ\overline{H J} : \square
Length of side adjacent to HJ\overline{H J} : \square (c) From parts (a) and (b), what can we conclude about parallelogram GHJKG H J K ? Check all that apply.

Studdy Solution

STEP 1

1. The coordinates of the vertices of the parallelogram are given as G(4,2),H(1,3),J(4,4),K(1,5) G(-4,2), H(1,3), J(4,-4), K(-1,-5) .
2. To determine if the parallelogram is a rectangle, rhombus, or square, we need to check the slopes and lengths of the sides.

STEP 2

1. Calculate the slope of HJ \overline{HJ} .
2. Calculate the slope of a side adjacent to HJ \overline{HJ} .
3. Calculate the length of HJ \overline{HJ} .
4. Calculate the length of a side adjacent to HJ \overline{HJ} .
5. Analyze the properties of the parallelogram based on slopes and lengths.

STEP 3

To find the slope of HJ \overline{HJ} , use the formula for the slope between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2):
Slope of HJ=y2y1x2x1 \text{Slope of } \overline{HJ} = \frac{y_2 - y_1}{x_2 - x_1}
For H(1,3) H(1,3) and J(4,4) J(4,-4) :
Slope of HJ=4341=73 \text{Slope of } \overline{HJ} = \frac{-4 - 3}{4 - 1} = \frac{-7}{3}

STEP 4

To find the slope of a side adjacent to HJ \overline{HJ} , consider GH \overline{GH} with points G(4,2) G(-4,2) and H(1,3) H(1,3) :
Slope of GH=321(4)=15 \text{Slope of } \overline{GH} = \frac{3 - 2}{1 - (-4)} = \frac{1}{5}

STEP 5

To find the length of HJ \overline{HJ} , use the distance formula:
Length of HJ=(x2x1)2+(y2y1)2 \text{Length of } \overline{HJ} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
For H(1,3) H(1,3) and J(4,4) J(4,-4) :
Length of HJ=(41)2+(43)2=32+(7)2=9+49=58 \text{Length of } \overline{HJ} = \sqrt{(4 - 1)^2 + (-4 - 3)^2} = \sqrt{3^2 + (-7)^2} = \sqrt{9 + 49} = \sqrt{58}

STEP 6

To find the length of a side adjacent to HJ \overline{HJ} , consider GH \overline{GH} :
Length of GH=(1(4))2+(32)2=52+12=25+1=26 \text{Length of } \overline{GH} = \sqrt{(1 - (-4))^2 + (3 - 2)^2} = \sqrt{5^2 + 1^2} = \sqrt{25 + 1} = \sqrt{26}

STEP 7

Analyze the properties: - Since the slopes of HJ \overline{HJ} and GH \overline{GH} are not negative reciprocals, GHJK GHJK is not a rectangle. - The lengths of HJ \overline{HJ} and GH \overline{GH} are not equal, so GHJK GHJK is not a rhombus. - Since it is neither a rectangle nor a rhombus, it cannot be a square. - Therefore, GHJK GHJK is none of these.
(a) Slope of HJ \overline{HJ} : 73 \frac{-7}{3}
Slope of side adjacent to HJ \overline{HJ} : 15 \frac{1}{5}
(b) Length of HJ \overline{HJ} : 58 \sqrt{58}
Length of side adjacent to HJ \overline{HJ} : 26 \sqrt{26}
(c) Conclusion: GHJK GHJK is none of these.

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