Math  /  Data & Statistics

QuestionConsider the below data for ALL PARTS of this question: 68322859454752554750\begin{array}{llllllllll}68 & 32 & 28 & 59 & 45 & 47 & 52 & 55 & 47 & 50\end{array} What is the sample MEDIAN? \qquad Note: Enter X.X AT LEAST ONE DIGIT BEFORE THE DECIMAL, ONE AFTER and round up AFTER all calculations. Thus, 7 is entered as 7.0;3.5627.0 ;-3.562 is entered as -3.6 ; 0.3750 is entered as 0.4;17.3510.4 ; 17.351 is entered as 17.4 \square A

Studdy Solution

STEP 1

What is this asking? Find the middle number in a set of numbers after putting them in order. Watch out! Don't forget to sort the numbers first!
Also, remember the special rule for finding the median when there's an even number of values.

STEP 2

1. Sort the data
2. Find the middle

STEP 3

Alright, let's **wrangle these numbers**!
We've got a bunch of numbers here, and to find the median, we need to put them in order from smallest to largest.
It's like lining up for recess, smallest in the front, tallest in the back!

STEP 4

So, our **unsorted** list is: 68,32,28,59,45,47,52,55,47,5068, 32, 28, 59, 45, 47, 52, 55, 47, 50.
Let's **sort** them!

STEP 5

And the **sorted** list is: 28,32,45,47,47,50,52,55,59,6828, 32, 45, 47, 47, 50, 52, 55, 59, 68.
Look at that, nice and organized!

STEP 6

Now, the **median** is the middle number.
It's like the VIP in the middle of the line.
Since we have an **even** number of values (1010 values), we need to find the **average** of the two middle numbers.
It's like having *two* VIPs!

STEP 7

Our two middle numbers are 4747 and 5050.
Let's **add them together** and **divide by** 22 to find their average.

STEP 8

47+502=972=48.5\frac{47 + 50}{2} = \frac{97}{2} = 48.5

STEP 9

So, our **median** is 48.548.5!

STEP 10

The sample median is 48.548.5.

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