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Math

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PROBLEM

Consider the following binomial probability distribution expression below. The number of trials, the number of successes, the probability of success and the probability of failure respectively are:
(127)(0.1)7(0.9)5\binom{12}{7}(0.1)^{7}(0.9)^{5} 7,0.1,0.9,127,0.1,0.9,12
12,7,0.1,0.912,7,0.1,0.9
12,7,0.9,0.112,7,0.9,0.1
7,0.9,12,0.17,0.9,12,0.1

STEP 1

1. The expression given is a binomial probability expression.
2. The binomial probability formula is given by:
$$ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k}
\] where n n is the number of trials, k k is the number of successes, p p is the probability of success, and 1p 1-p is the probability of failure.

STEP 2

1. Identify the components of the binomial expression.
2. Match the components to the correct option.

STEP 3

Identify the components from the expression (127)(0.1)7(0.9)5\binom{12}{7}(0.1)^{7}(0.9)^{5}:
- Number of trials n=12 n = 12
- Number of successes k=7 k = 7
- Probability of success p=0.1 p = 0.1
- Probability of failure 1p=0.9 1-p = 0.9

SOLUTION

Match the identified components to the correct option:
- Number of trials n=12 n = 12
- Number of successes k=7 k = 7
- Probability of success p=0.1 p = 0.1
- Probability of failure 1p=0.9 1-p = 0.9
The correct option is:
12,7,0.1,0.9 12, 7, 0.1, 0.9 The correct answer is:
12,7,0.1,0.9 \boxed{12, 7, 0.1, 0.9}

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