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Math

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PROBLEM

Consider the system of linear equations shown below:
2x+9=4yxy=2\begin{array}{c} 2 x+9=-4 y \\ -x-y=2 \end{array} Create the coefficient matrix, DD

STEP 1

1. The system of linear equations is given in the standard form ax+by=c ax + by = c .
2. We need to extract coefficients of x x and y y from each equation to form the coefficient matrix.

STEP 2

1. Rearrange each equation to the standard form ax+by=c ax + by = c .
2. Extract coefficients of x x and y y to form the coefficient matrix D D .

STEP 3

Rearrange the first equation 2x+9=4y 2x + 9 = -4y to the standard form:
2x+4y=9 2x + 4y = -9 This is done by adding 4y 4y to both sides and subtracting 9 from both sides.

STEP 4

The second equation is already in the standard form:
xy=2 -x - y = 2 No rearrangement is needed.

STEP 5

Extract the coefficients of x x and y y from both equations:
From the first equation 2x+4y=9 2x + 4y = -9 , the coefficients are 2 2 and 4 4 .
From the second equation xy=2 -x - y = 2 , the coefficients are 1 -1 and 1 -1 .

SOLUTION

Form the coefficient matrix D D using the extracted coefficients:
D=[2411] D = \begin{bmatrix} 2 & 4 \\ -1 & -1 \end{bmatrix} This matrix represents the coefficients of x x and y y in the system of equations.

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