Math

QuestionConvert 1.5×1091.5 \times 10^{9} eV to calories.

Studdy Solution

STEP 1

Assumptions1. The energy value given is 1.5×1091.5 \times10^{9} electron-volts (eV). . We need to convert this energy value to calories.
3. The conversion factors are as follows -1 eV = 1.602×10191.602 \times10^{-19} joules (J) -1 cal =4.184 J

STEP 2

First, we need to convert the energy value from electron-volts to joules. We can do this by multiplying the energy value by the conversion factor.
EnergyJ=EnergyeVtimesConversionfactoreVtoJEnergy_{J} = Energy_{eV} \\times Conversion\, factor_{eV\, to\, J}

STEP 3

Now, plug in the given values for the energy value and the conversion factor to calculate the energy in joules.
EnergyJ=1.5×109eVtimes1.602×1019J/eVEnergy_{J} =1.5 \times10^{9}\, eV \\times1.602 \times10^{-19}\, J/eV

STEP 4

Calculate the energy amount in joules.
EnergyJ=1.×109times1.602×1019=0.2403JEnergy_{J} =1. \times10^{9} \\times1.602 \times10^{-19} =0.2403\, J

STEP 5

Now that we have the energy amount in joules, we can convert this to calories. We can do this by dividing the energy value by the conversion factor.
Energycal=EnergyJ/ConversionfactorJtocalEnergy_{cal} = Energy_{J} / Conversion\, factor_{J\, to\, cal}

STEP 6

Plug in the values for the energy amount in joules and the conversion factor to calculate the energy in calories.
Energycal=0.2403J/4.184J/calEnergy_{cal} =0.2403\, J /4.184\, J/cal

STEP 7

Calculate the energy amount in calories.
Energycal=0.2403/4.184=0.0574calEnergy_{cal} =0.2403 /4.184 =0.0574\, calThe energy of 1.5×1091.5 \times10^{9} electron-volts is equivalent to0.0574 calories.

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