Question Convert the binary number 110011 to its decimal equivalent.

Studdy Solution

STEP 1

1. The number 110011 is in binary (base-2) notation.
2. Denary refers to the decimal number system (base-10).
3. To convert from binary to decimal, we multiply each digit by $2$ raised to the power of its position, starting from the right with position $0$ .

STEP 2

1. Identify each digit of the binary number and its positional value.
2. Convert each binary digit to its decimal equivalent using its positional value.
3. Sum the decimal values to get the final denary (decimal) number.

STEP 3

Identify each digit of the binary number 110011 and its positional value, starting from the rightmost digit.
$1 \times 2^5 + 1 \times 2^4 + 0 \times 2^3 + 0 \times 2^2 + 1 \times 2^1 + 1 \times 2^0$

STEP 4

Convert each binary digit to its decimal equivalent using its positional value.
$1 \times 2^5 = 32$ $1 \times 2^4 = 16$ $0 \times 2^3 = 0$ $0 \times 2^2 = 0$ $1 \times 2^1 = 2$ $1 \times 2^0 = 1$

STEP 5

Sum the decimal values to get the final denary (decimal) number.
$32 + 16 + 0 + 0 + 2 + 1 = 51$
The binary number 110011 in denary (decimal) is 51.

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Question Convert the binary number 110011 to its decimal equivalent.

Studdy Solution

STEP 1

1. The number 110011 is in binary (base-2) notation.
2. Denary refers to the decimal number system (base-10).
3. To convert from binary to decimal, we multiply each digit by $2$ raised to the power of its position, starting from the right with position $0$ .

STEP 2

1. Identify each digit of the binary number and its positional value.
2. Convert each binary digit to its decimal equivalent using its positional value.
3. Sum the decimal values to get the final denary (decimal) number.

STEP 3

Identify each digit of the binary number 110011 and its positional value, starting from the rightmost digit.
$1 \times 2^5 + 1 \times 2^4 + 0 \times 2^3 + 0 \times 2^2 + 1 \times 2^1 + 1 \times 2^0$

STEP 4

Convert each binary digit to its decimal equivalent using its positional value.
$1 \times 2^5 = 32$ $1 \times 2^4 = 16$ $0 \times 2^3 = 0$ $0 \times 2^2 = 0$ $1 \times 2^1 = 2$ $1 \times 2^0 = 1$

STEP 5

Sum the decimal values to get the final denary (decimal) number.
$32 + 16 + 0 + 0 + 2 + 1 = 51$
The binary number 110011 in denary (decimal) is 51.

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Question Convert the binary number 110011 to its decimal equivalent.

Studdy Solution

STEP 1

1. The number 110011 is in binary (base-2) notation.2. Denary refers to the decimal number system (base-10).3. To convert from binary to decimal, we multiply each digit by 222 raised to the power of its position, starting from the right with position 000.

STEP 2

1. Identify each digit of the binary number and its positional value.2. Convert each binary digit to its decimal equivalent using its positional value.3. Sum the decimal values to get the final denary (decimal) number.

STEP 3

Identify each digit of the binary number 110011 and its positional value, starting from the rightmost digit.1×25+1×24+0×23+0×22+1×21+1×20 1 \times 2^5 + 1 \times 2^4 + 0 \times 2^3 + 0 \times 2^2 + 1 \times 2^1 + 1 \times 2^0 1×25+1×24+0×23+0×22+1×21+1×20

STEP 4

Convert each binary digit to its decimal equivalent using its positional value.1×25=32 1 \times 2^5 = 32 1×25=32 1×24=16 1 \times 2^4 = 16 1×24=16 0×23=0 0 \times 2^3 = 0 0×23=0 0×22=0 0 \times 2^2 = 0 0×22=0 1×21=2 1 \times 2^1 = 2 1×21=2 1×20=1 1 \times 2^0 = 1 1×20=1

STEP 5

Sum the decimal values to get the final denary (decimal) number.32+16+0+0+2+1=51 32 + 16 + 0 + 0 + 2 + 1 = 51 32+16+0+0+2+1=51The binary number 110011 in denary (decimal) is 51.

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1. The number 110011 is in binary (base-2) notation.
2. Denary refers to the decimal number system (base-10).
3. To convert from binary to decimal, we multiply each digit by $2$ raised to the power of its position, starting from the right with position $0$ .

1. Identify each digit of the binary number and its positional value.
2. Convert each binary digit to its decimal equivalent using its positional value.
3. Sum the decimal values to get the final denary (decimal) number.

Identify each digit of the binary number 110011 and its positional value, starting from the rightmost digit.
$1 \times 2^5 + 1 \times 2^4 + 0 \times 2^3 + 0 \times 2^2 + 1 \times 2^1 + 1 \times 2^0$

Convert each binary digit to its decimal equivalent using its positional value.
$1 \times 2^5 = 32$ $1 \times 2^4 = 16$ $0 \times 2^3 = 0$ $0 \times 2^2 = 0$ $1 \times 2^1 = 2$ $1 \times 2^0 = 1$

Sum the decimal values to get the final denary (decimal) number.
$32 + 16 + 0 + 0 + 2 + 1 = 51$
The binary number 110011 in denary (decimal) is 51.