Math  /  Geometry

QuestionConvert the following polar coordinates to rectangular coordinates equations. (Here aa is a constant number.) r=ar=a \square r=asec(θ)r=a \sec (\theta) \square r=acsc(θ)r=a \csc (\theta) \square r=2asin(θ)r=2 a \sin (\theta) \square r=2acos(θ)r=2 a \cos (\theta) \square r=asec(2θ)r=a \sec (2 \theta) \square θ=π4\theta=\frac{\pi}{4} \square
Drag or tap the options below to fill in the blanks x2y2=ay=ay=xx2+(ya)2=a2x=a)2+y2=a2x2+y2=a2\left.x^{2}-y^{2}=a y=a y=x x^{2}+(y-a)^{2}=a^{2} x=a\right)^{2}+y^{2}=a^{2} x^{2}+y^{2}=a^{2}

Studdy Solution

STEP 1

1. The polar coordinates are given in the form r=f(θ) r = f(\theta) .
2. The conversion from polar to rectangular coordinates involves using the relationships x=rcos(θ) x = r \cos(\theta) and y=rsin(θ) y = r \sin(\theta) .

STEP 2

1. Convert r=a r = a to rectangular coordinates.
2. Convert r=asec(θ) r = a \sec(\theta) to rectangular coordinates.
3. Convert r=acsc(θ) r = a \csc(\theta) to rectangular coordinates.
4. Convert r=2asin(θ) r = 2a \sin(\theta) to rectangular coordinates.
5. Convert r=2acos(θ) r = 2a \cos(\theta) to rectangular coordinates.
6. Convert r=asec(2θ) r = a \sec(2\theta) to rectangular coordinates.
7. Convert θ=π4 \theta = \frac{\pi}{4} to rectangular coordinates.

STEP 3

Convert r=a r = a to rectangular coordinates:
Using the identity x2+y2=r2 x^2 + y^2 = r^2 , we substitute r=a r = a :
x2+y2=a2 x^2 + y^2 = a^2

STEP 4

Convert r=asec(θ) r = a \sec(\theta) to rectangular coordinates:
Since sec(θ)=1cos(θ) \sec(\theta) = \frac{1}{\cos(\theta)} , we have rcos(θ)=a r \cos(\theta) = a .
Thus, x=a x = a .

STEP 5

Convert r=acsc(θ) r = a \csc(\theta) to rectangular coordinates:
Since csc(θ)=1sin(θ) \csc(\theta) = \frac{1}{\sin(\theta)} , we have rsin(θ)=a r \sin(\theta) = a .
Thus, y=a y = a .

STEP 6

Convert r=2asin(θ) r = 2a \sin(\theta) to rectangular coordinates:
Multiply both sides by r r to get r2=2arsin(θ) r^2 = 2a r \sin(\theta) .
Substitute r2=x2+y2 r^2 = x^2 + y^2 and rsin(θ)=y r \sin(\theta) = y :
x2+y2=2ay x^2 + y^2 = 2a y

STEP 7

Convert r=2acos(θ) r = 2a \cos(\theta) to rectangular coordinates:
Multiply both sides by r r to get r2=2arcos(θ) r^2 = 2a r \cos(\theta) .
Substitute r2=x2+y2 r^2 = x^2 + y^2 and rcos(θ)=x r \cos(\theta) = x :
x2+y2=2ax x^2 + y^2 = 2a x

STEP 8

Convert r=asec(2θ) r = a \sec(2\theta) to rectangular coordinates:
Using the identity sec(2θ)=1cos(2θ) \sec(2\theta) = \frac{1}{\cos(2\theta)} , we have rcos(2θ)=a r \cos(2\theta) = a .
This is more complex to convert directly, but typically involves using double angle identities and further algebraic manipulation.

STEP 9

Convert θ=π4 \theta = \frac{\pi}{4} to rectangular coordinates:
Using the identity tan(θ)=yx \tan(\theta) = \frac{y}{x} , for θ=π4 \theta = \frac{\pi}{4} , we have tan(π4)=1 \tan\left(\frac{\pi}{4}\right) = 1 .
Thus, y=x y = x .
The rectangular coordinates equations are:
1. x2+y2=a2 x^2 + y^2 = a^2
2. x=a x = a
3. y=a y = a
4. x2+(ya)2=a2 x^2 + (y - a)^2 = a^2
5. (xa)2+y2=a2 (x - a)^2 + y^2 = a^2
6. Further manipulation needed for r=asec(2θ) r = a \sec(2\theta)
7. y=x y = x

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