QuestionComplete the table for $y=\frac{1}{2}x-2$ . What are the values of $A$ and $B$ ? Then, use the table to draw the line on the axes.
\begin{tabular}{c|c|c|c|c|c} $x$ & -2 & -1 & 0 & 1 & 2 \\ \hline $y$ & -3 & $A$ & $B$ & -1.5 & -1 \end{tabular}

Studdy Solution

STEP 1

Assumptions1. The equation of the line is $y=\frac{1}{} x-$ . We are asked to find the values of $y$ when $x$ is -1 and0, which are represented as $A$ and $B$ respectively in the table.

STEP 2

First, we need to find the value of $y$ when $x$ is -1. We can do this by substituting $x$ = -1 into the equation.
$y = \frac{1}{2} \times -1 -2$

STEP 3

Calculate the value of $y$ when $x$ is -1.
$y = -\frac{1}{2} -2 = -\frac{5}{2} = -2.5$ So, $A = -2.5$ .

STEP 4

Next, we need to find the value of $y$ when $x$ is0. We can do this by substituting $x$ =0 into the equation.
$y = \frac{1}{2} \times0 -2$

STEP 5

Calculate the value of $y$ when $x$ is0.
$y =0 -2 = -2$ So, $B = -2$ .

STEP 6

Now, we have the completed table\begin{tabular}{c|c|c|c|c|c} $x$ & -2 & -1 &0 &1 &2 \\ \hline $y$ & -3 & -2.5 & -2 & -1.5 & -1\end{tabular}

STEP 7

For part b), we are asked to plot the points from the table and draw the line $y=\frac{1}{2} x-2$ . The points to plot are (-2, -3), (-1, -2.5), (0, -2), (1, -1.5), and (2, -1).

STEP 8

After plotting these points on the graph, we can draw a straight line through them. This line represents the equation $y=\frac{1}{2} x-2$ .
Values that should replace $A$ and $B$ are -2.5 and -2 respectively.

Was this helpful?

QuestionComplete the table for $y=\frac{1}{2}x-2$ . What are the values of $A$ and $B$ ? Then, use the table to draw the line on the axes.
\begin{tabular}{c|c|c|c|c|c} $x$ & -2 & -1 & 0 & 1 & 2 \\ \hline $y$ & -3 & $A$ & $B$ & -1.5 & -1 \end{tabular}

Studdy Solution

STEP 1

Assumptions1. The equation of the line is $y=\frac{1}{} x-$ . We are asked to find the values of $y$ when $x$ is -1 and0, which are represented as $A$ and $B$ respectively in the table.

STEP 2

First, we need to find the value of $y$ when $x$ is -1. We can do this by substituting $x$ = -1 into the equation.
$y = \frac{1}{2} \times -1 -2$

STEP 3

Calculate the value of $y$ when $x$ is -1.
$y = -\frac{1}{2} -2 = -\frac{5}{2} = -2.5$ So, $A = -2.5$ .

STEP 4

Next, we need to find the value of $y$ when $x$ is0. We can do this by substituting $x$ =0 into the equation.
$y = \frac{1}{2} \times0 -2$

STEP 5

Calculate the value of $y$ when $x$ is0.
$y =0 -2 = -2$ So, $B = -2$ .

STEP 6

Now, we have the completed table\begin{tabular}{c|c|c|c|c|c} $x$ & -2 & -1 &0 &1 &2 \\ \hline $y$ & -3 & -2.5 & -2 & -1.5 & -1\end{tabular}

STEP 7

For part b), we are asked to plot the points from the table and draw the line $y=\frac{1}{2} x-2$ . The points to plot are (-2, -3), (-1, -2.5), (0, -2), (1, -1.5), and (2, -1).

STEP 8

After plotting these points on the graph, we can draw a straight line through them. This line represents the equation $y=\frac{1}{2} x-2$ .
Values that should replace $A$ and $B$ are -2.5 and -2 respectively.

Get Studdy

Studdy solves anything!

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

QuestionComplete the table for y=12x−2y=\frac{1}{2}x-2y=21​x−2. What are the values of AAA and BBB? Then, use the table to draw the line on the axes. \begin{tabular}{c|c|c|c|c|c} xxx & -2 & -1 & 0 & 1 & 2 \\ \hlineyyy & -3 & AAA & BBB & -1.5 & -1 \end{tabular}

Studdy Solution

STEP 1

Assumptions1. The equation of the line is y=1x−y=\frac{1}{} x-y=1​x− . We are asked to find the values of yyy when xxx is -1 and0, which are represented as AAA and BBB respectively in the table.

STEP 2

First, we need to find the value of yyy when xxx is -1. We can do this by substituting xxx = -1 into the equation.y=12×−1−2y = \frac{1}{2} \times -1 -2y=21​×−1−2

STEP 3

Calculate the value of yyy when xxx is -1.y=−12−2=−52=−2.5y = -\frac{1}{2} -2 = -\frac{5}{2} = -2.5y=−21​−2=−25​=−2.5So, A=−2.5A = -2.5A=−2.5.

STEP 4

Next, we need to find the value of yyy when xxx is0. We can do this by substituting xxx =0 into the equation.y=12×0−2y = \frac{1}{2} \times0 -2y=21​×0−2

STEP 5

Calculate the value of yyy when xxx is0.y=0−2=−2y =0 -2 = -2y=0−2=−2So, B=−2B = -2B=−2.

STEP 6

Now, we have the completed table\begin{tabular}{c|c|c|c|c|c} xxx & -2 & -1 &0 &1 &2 \\ \hlineyyy & -3 & -2.5 & -2 & -1.5 & -1\end{tabular}

STEP 7

For part b), we are asked to plot the points from the table and draw the line y=12x−2y=\frac{1}{2} x-2y=21​x−2. The points to plot are (-2, -3), (-1, -2.5), (0, -2), (1, -1.5), and (2, -1).

STEP 8

After plotting these points on the graph, we can draw a straight line through them. This line represents the equation y=12x−2y=\frac{1}{2} x-2y=21​x−2.Values that should replace AAA and BBB are -2.5 and -2 respectively.

Get Studdy

Studdy solves anything!

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

QuestionComplete the table for $y=\frac{1}{2}x-2$ . What are the values of $A$ and $B$ ? Then, use the table to draw the line on the axes.
\begin{tabular}{c|c|c|c|c|c} $x$ & -2 & -1 & 0 & 1 & 2 \\ \hline $y$ & -3 & $A$ & $B$ & -1.5 & -1 \end{tabular}

Assumptions1. The equation of the line is $y=\frac{1}{} x-$ . We are asked to find the values of $y$ when $x$ is -1 and0, which are represented as $A$ and $B$ respectively in the table.

First, we need to find the value of $y$ when $x$ is -1. We can do this by substituting $x$ = -1 into the equation.
$y = \frac{1}{2} \times -1 -2$

Calculate the value of $y$ when $x$ is -1.
$y = -\frac{1}{2} -2 = -\frac{5}{2} = -2.5$ So, $A = -2.5$ .

Next, we need to find the value of $y$ when $x$ is0. We can do this by substituting $x$ =0 into the equation.
$y = \frac{1}{2} \times0 -2$

Calculate the value of $y$ when $x$ is0.
$y =0 -2 = -2$ So, $B = -2$ .

Now, we have the completed table\begin{tabular}{c|c|c|c|c|c} $x$ & -2 & -1 &0 &1 &2 \\ \hline $y$ & -3 & -2.5 & -2 & -1.5 & -1\end{tabular}

For part b), we are asked to plot the points from the table and draw the line $y=\frac{1}{2} x-2$ . The points to plot are (-2, -3), (-1, -2.5), (0, -2), (1, -1.5), and (2, -1).

After plotting these points on the graph, we can draw a straight line through them. This line represents the equation $y=\frac{1}{2} x-2$ .
Values that should replace $A$ and $B$ are -2.5 and -2 respectively.