Math  /  Calculus

Questioncos3(4x)sin(4x)dx\int \cos ^{3}(4 x) \sin (4 x) d x

Studdy Solution

STEP 1

What is this asking? We need to find the indefinite integral of cos3(4x)sin(4x)\cos^3(4x) \cdot \sin(4x) with respect to xx.
Basically, we're looking for a function whose derivative is cos3(4x)sin(4x)\cos^3(4x) \cdot \sin(4x). Watch out! Don't forget the chain rule and remember to add the constant of integration since it's an indefinite integral!

STEP 2

1. U-Substitution
2. Integrate
3. Substitute Back

STEP 3

Let's **define** our *u*!
We'll let u=cos(4x)u = \cos(4x).
This is a strategic choice because the derivative of cos(4x)\cos(4x) is related to sin(4x)\sin(4x), which is also in our integral.
This substitution will simplify things greatly!

STEP 4

Now, let's **find** dudu.
Taking the derivative of uu with respect to xx, we get dudx=4sin(4x)\frac{du}{dx} = -4\sin(4x).
Remember the chain rule!
Multiplying both sides by dxdx gives us du=4sin(4x)dxdu = -4\sin(4x) dx.

STEP 5

We want to **replace** sin(4x)dx\sin(4x) dx in our original integral with dudu.
So, let's **solve** for sin(4x)dx\sin(4x) dx in terms of dudu.
Dividing both sides of du=4sin(4x)dxdu = -4\sin(4x) dx by 4-4 gives us sin(4x)dx=14du\sin(4x) dx = -\frac{1}{4} du.

STEP 6

Now, let's **rewrite** our integral using the *u* substitution.
Substituting u=cos(4x)u = \cos(4x) and sin(4x)dx=14du\sin(4x) dx = -\frac{1}{4} du, our integral becomes u3(14)du. \int u^3 \cdot \left(-\frac{1}{4}\right) du. We can **pull** the constant 14-\frac{1}{4} out front: 14u3du. -\frac{1}{4} \int u^3 du.

STEP 7

Time to **integrate**!
Using the power rule for integration, we add 1 to the exponent and divide by the new exponent: 14u3du=14u44+C. -\frac{1}{4} \int u^3 du = -\frac{1}{4} \cdot \frac{u^4}{4} + C. This simplifies to 116u4+C-\frac{1}{16}u^4 + C, where *C* is our constant of integration.

STEP 8

Almost there!
Let's **substitute** cos(4x)\cos(4x) back in for uu to get our final answer in terms of xx: 116(cos(4x))4+C. -\frac{1}{16}(\cos(4x))^4 + C. This can also be written as 116cos4(4x)+C-\frac{1}{16}\cos^4(4x) + C.

STEP 9

Our **final answer** is 116cos4(4x)+C-\frac{1}{16}\cos^4(4x) + C.

Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord