Math / Geometry

QuestionCOUNTING RISE OVER RUN To determine the slope of the line, count and record the rise over run! ताल $\qquad$ $\qquad$ जबत्य - 6 5 ovamem -9 1

Studdy Solution

STEP 1

What is this asking? Find the slope of the line that goes through the points $(-9, 9)$ and $(1, -1)$ . Watch out! Don't mix up the x and y coordinates!
Also, remember that slope is rise over run, not run over rise.

STEP 2

1. Find the rise.
2. Find the run.
3. Calculate the slope.

STEP 3

The rise is the change in the y-values.
We go from $y_1 = 9$ to $y_2 = -1$ .

STEP 4

Let's calculate the change: $y_2 - y_1 = -1 - 9 = \mathbf{-10}$ .
So, our rise is $\mathbf{-10}$ .
This means we are going down $\mathbf{10}$ units!

STEP 5

The run is the change in the x-values.
We go from $x_1 = -9$ to $x_2 = 1$ .

STEP 6

Let's calculate the change: $x_2 - x_1 = 1 - (-9) = 1 + 9 = \mathbf{10}$ .
Our run is $\mathbf{10}$ , meaning we move $\mathbf{10}$ units to the right!

STEP 7

Remember, slope is rise over run.

STEP 8

We found that the rise is $-10$ and the run is $10$ .

STEP 9

So, the slope is: $\frac{\text{rise}}{\text{run}} = \frac{-10}{10} = \frac{-1 \cdot 10}{1 \cdot 10} = \frac{-1}{1} = \mathbf{-1}$

STEP 10

The slope of the line is $\mathbf{-1}$ .

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QuestionCOUNTING RISE OVER RUN To determine the slope of the line, count and record the rise over run! ताल $\qquad$ $\qquad$ जबत्य - 6 5 ovamem -9 1

Studdy Solution

STEP 1

What is this asking? Find the slope of the line that goes through the points $(-9, 9)$ and $(1, -1)$ . Watch out! Don't mix up the x and y coordinates!
Also, remember that slope is rise over run, not run over rise.

STEP 2

1. Find the rise.
2. Find the run.
3. Calculate the slope.

STEP 3

The rise is the change in the y-values.
We go from $y_1 = 9$ to $y_2 = -1$ .

STEP 4

Let's calculate the change: $y_2 - y_1 = -1 - 9 = \mathbf{-10}$ .
So, our rise is $\mathbf{-10}$ .
This means we are going down $\mathbf{10}$ units!

STEP 5

The run is the change in the x-values.
We go from $x_1 = -9$ to $x_2 = 1$ .

STEP 6

Let's calculate the change: $x_2 - x_1 = 1 - (-9) = 1 + 9 = \mathbf{10}$ .
Our run is $\mathbf{10}$ , meaning we move $\mathbf{10}$ units to the right!

STEP 7

Remember, slope is rise over run.

STEP 8

We found that the rise is $-10$ and the run is $10$ .

STEP 9

So, the slope is: $\frac{\text{rise}}{\text{run}} = \frac{-10}{10} = \frac{-1 \cdot 10}{1 \cdot 10} = \frac{-1}{1} = \mathbf{-1}$

STEP 10

The slope of the line is $\mathbf{-1}$ .

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QuestionCOUNTING RISE OVER RUN To determine the slope of the line, count and record the rise over run! ताल \qquad \qquad जबत्य - 6 5 ovamem -9 1

Studdy Solution

STEP 1

What is this asking? Find the slope of the line that goes through the points (−9,9)(-9, 9)(−9,9) and (1,−1)(1, -1)(1,−1). Watch out! Don't mix up the *x* and *y* coordinates!Also, remember that slope is rise over run, not run over rise.

STEP 2

1. Find the rise.2. Find the run.3. Calculate the slope.

STEP 3

The **rise** is the change in the *y*-values.We go from y1=9y_1 = 9y1​=9 to y2=−1y_2 = -1y2​=−1.

STEP 4

Let's calculate the change: y2−y1=−1−9=−10y_2 - y_1 = -1 - 9 = \mathbf{-10}y2​−y1​=−1−9=−10.So, our **rise** is −10\mathbf{-10}−10.This means we are going *down* 10\mathbf{10}10 units!

STEP 5

The **run** is the change in the *x*-values.We go from x1=−9x_1 = -9x1​=−9 to x2=1x_2 = 1x2​=1.

STEP 6

Let's calculate the change: x2−x1=1−(−9)=1+9=10x_2 - x_1 = 1 - (-9) = 1 + 9 = \mathbf{10}x2​−x1​=1−(−9)=1+9=10.Our **run** is 10\mathbf{10}10, meaning we move 10\mathbf{10}10 units to the *right*!

STEP 7

Remember, **slope** is **rise** over **run**.

STEP 8

We found that the **rise** is −10-10−10 and the **run** is 101010.

STEP 9

So, the **slope** is: riserun=−1010=−1⋅101⋅10=−11=−1 \frac{\text{rise}}{\text{run}} = \frac{-10}{10} = \frac{-1 \cdot 10}{1 \cdot 10} = \frac{-1}{1} = \mathbf{-1} runrise​=10−10​=1⋅10−1⋅10​=1−1​=−1

STEP 10

The slope of the line is −1\mathbf{-1}−1.

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QuestionCOUNTING RISE OVER RUN To determine the slope of the line, count and record the rise over run! ताल $\qquad$ $\qquad$ जबत्य - 6 5 ovamem -9 1

What is this asking? Find the slope of the line that goes through the points $(-9, 9)$ and $(1, -1)$ . Watch out! Don't mix up the x and y coordinates!
Also, remember that slope is rise over run, not run over rise.

1. Find the rise.
2. Find the run.
3. Calculate the slope.

The rise is the change in the y-values.
We go from $y_1 = 9$ to $y_2 = -1$ .

Let's calculate the change: $y_2 - y_1 = -1 - 9 = \mathbf{-10}$ .
So, our rise is $\mathbf{-10}$ .
This means we are going down $\mathbf{10}$ units!

The run is the change in the x-values.
We go from $x_1 = -9$ to $x_2 = 1$ .

Let's calculate the change: $x_2 - x_1 = 1 - (-9) = 1 + 9 = \mathbf{10}$ .
Our run is $\mathbf{10}$ , meaning we move $\mathbf{10}$ units to the right!

Remember, slope is rise over run.

We found that the rise is $-10$ and the run is $10$ .

So, the slope is: $\frac{\text{rise}}{\text{run}} = \frac{-10}{10} = \frac{-1 \cdot 10}{1 \cdot 10} = \frac{-1}{1} = \mathbf{-1}$

The slope of the line is $\mathbf{-1}$ .