Math / Algebra

Questiond) $\frac{x}{5}+1=2$

Studdy Solution

STEP 1

1. The equation $\frac{x}{5} + 1 = 2$ is a linear equation in one variable.
2. The goal is to solve for $x$ .
3. Basic algebraic operations such as subtraction and multiplication will be used.

STEP 2

1. Isolate the term containing $x$ .
2. Solve for $x$ by performing algebraic operations.
3. Check the solution by substituting it back into the original equation.

STEP 3

To isolate the term containing $x$ , subtract 1 from both sides of the equation:
$\frac{x}{5} + 1 - 1 = 2 - 1$
This simplifies to:
$\frac{x}{5} = 1$

STEP 4

To solve for $x$ , multiply both sides of the equation by 5 to eliminate the fraction:
$5 \times \frac{x}{5} = 5 \times 1$
This simplifies to:
$x = 5$

STEP 5

Check the solution by substituting $x = 5$ back into the original equation:
$\frac{5}{5} + 1 = 2$
Simplify the left-hand side:
$1 + 1 = 2$
Since both sides are equal, the solution is verified.
The solution is:
$\boxed{5}$

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Questiond) $\frac{x}{5}+1=2$

Studdy Solution

STEP 1

1. The equation $\frac{x}{5} + 1 = 2$ is a linear equation in one variable.
2. The goal is to solve for $x$ .
3. Basic algebraic operations such as subtraction and multiplication will be used.

STEP 2

1. Isolate the term containing $x$ .
2. Solve for $x$ by performing algebraic operations.
3. Check the solution by substituting it back into the original equation.

STEP 3

To isolate the term containing $x$ , subtract 1 from both sides of the equation:
$\frac{x}{5} + 1 - 1 = 2 - 1$
This simplifies to:
$\frac{x}{5} = 1$

STEP 4

To solve for $x$ , multiply both sides of the equation by 5 to eliminate the fraction:
$5 \times \frac{x}{5} = 5 \times 1$
This simplifies to:
$x = 5$

STEP 5

Check the solution by substituting $x = 5$ back into the original equation:
$\frac{5}{5} + 1 = 2$
Simplify the left-hand side:
$1 + 1 = 2$
Since both sides are equal, the solution is verified.
The solution is:
$\boxed{5}$

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Questiond) x5+1=2\frac{x}{5}+1=25x​+1=2

Studdy Solution

STEP 1

1. The equation x5+1=2 \frac{x}{5} + 1 = 2 5x​+1=2 is a linear equation in one variable.2. The goal is to solve for x x x.3. Basic algebraic operations such as subtraction and multiplication will be used.

STEP 2

1. Isolate the term containing x x x.2. Solve for x x x by performing algebraic operations.3. Check the solution by substituting it back into the original equation.

STEP 3

To isolate the term containing x x x, subtract 1 from both sides of the equation:x5+1−1=2−1 \frac{x}{5} + 1 - 1 = 2 - 1 5x​+1−1=2−1This simplifies to:x5=1 \frac{x}{5} = 1 5x​=1

STEP 4

To solve for x x x, multiply both sides of the equation by 5 to eliminate the fraction:5×x5=5×1 5 \times \frac{x}{5} = 5 \times 1 5×5x​=5×1This simplifies to:x=5 x = 5 x=5

STEP 5

Check the solution by substituting x=5 x = 5 x=5 back into the original equation:55+1=2 \frac{5}{5} + 1 = 2 55​+1=2Simplify the left-hand side:1+1=2 1 + 1 = 2 1+1=2Since both sides are equal, the solution is verified. The solution is:5 \boxed{5} 5​

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Questiond) $\frac{x}{5}+1=2$

1. The equation $\frac{x}{5} + 1 = 2$ is a linear equation in one variable.
2. The goal is to solve for $x$ .
3. Basic algebraic operations such as subtraction and multiplication will be used.

1. Isolate the term containing $x$ .
2. Solve for $x$ by performing algebraic operations.
3. Check the solution by substituting it back into the original equation.

To isolate the term containing $x$ , subtract 1 from both sides of the equation:
$\frac{x}{5} + 1 - 1 = 2 - 1$
This simplifies to:
$\frac{x}{5} = 1$

To solve for $x$ , multiply both sides of the equation by 5 to eliminate the fraction:
$5 \times \frac{x}{5} = 5 \times 1$
This simplifies to:
$x = 5$

Check the solution by substituting $x = 5$ back into the original equation:
$\frac{5}{5} + 1 = 2$
Simplify the left-hand side:
$1 + 1 = 2$
Since both sides are equal, the solution is verified.
The solution is:
$\boxed{5}$