Math  /  Numbers & Operations

QuestionDarcey left her house at 5.31 am and arrived back at 7.54 pm. How long was she out of her house for? Give your answer in hours and minutes.

Studdy Solution

STEP 1

1. Darcey left her house at 5:31 AM.
2. Darcey arrived back at 7:54 PM.
3. We need to calculate the total time Darcey was out of her house in hours and minutes.

STEP 2

1. Convert times to a 24-hour format.
2. Calculate the total duration in minutes.
3. Convert the total duration from minutes to hours and minutes.

STEP 3

Convert the times to a 24-hour format to simplify calculation.
- 5:31 AM remains 05:31. - 7:54 PM converts to 19:54.

STEP 4

Calculate the total duration in minutes by finding the difference between the two times.
- Start time: 05:31 - End time: 19:54
Calculate the difference in hours and minutes separately:
- Hours difference: 195=14 19 - 5 = 14 hours - Minutes difference: 5431=23 54 - 31 = 23 minutes
Total duration in minutes: 14×60+23=840+23=863 14 \times 60 + 23 = 840 + 23 = 863 minutes

STEP 5

Convert the total duration from minutes to hours and minutes.
- Total minutes: 863 - Hours: 86360=14 \left\lfloor \frac{863}{60} \right\rfloor = 14 hours - Remaining minutes: 863mod60=23 863 \mod 60 = 23 minutes
Darcey was out of her house for:
14 hours and 23 minutes\boxed{14 \text{ hours and } 23 \text{ minutes}}

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