Math

Question Find all numbers xx that are 9 units away from 11, expressed using absolute value.

Studdy Solution

STEP 1

Assumptions
1. The distance between two numbers on the number line is the absolute value of their difference.
2. The number from which the distance is measured is 11.
3. The distance we are interested in is 9.

STEP 2

To describe the numbers that are at a distance of 9 from the number 11, we use the concept of absolute value. The absolute value of a number is its distance from 0 on the number line.
xa=b|x - a| = b
Here, aa is the number from which we are measuring the distance, bb is the distance, and xx is the number we are trying to find.

STEP 3

In our case, a=11a = 11 and b=9b = 9. We can write the equation as:
x11=9|x - 11| = 9

STEP 4

The absolute value equation x11=9|x - 11| = 9 means that the distance between xx and 11 is 9. This can happen in two cases:
1. xx is 9 units greater than 11.
2. xx is 9 units less than 11.

STEP 5

For the first case, where xx is 9 units greater than 11, we can write:
x11=9x - 11 = 9

STEP 6

Solve for xx in the first case:
x=9+11x = 9 + 11
x=20x = 20

STEP 7

For the second case, where xx is 9 units less than 11, we can write:
x11=9x - 11 = -9

STEP 8

Solve for xx in the second case:
x=9+11x = -9 + 11
x=2x = 2

STEP 9

Combining both cases, the numbers that are at a distance of 9 from the number 11 are 2 and 20. We can express this using absolute value notation as:
x11=9|x - 11| = 9
The solutions are x=2x = 2 and x=20x = 20.

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