Math  /  Algebra

QuestionDescribe how the graph of y=2xy=2 x is the same and different from the graph of y=2x7y=2 x-7 Explain or show your reasoning.

Studdy Solution

STEP 1

What is this asking? How are the graphs of y=2xy = 2x and y=2x7y = 2x - 7 similar and different? Watch out! Don't forget to discuss both similarities *and* differences!

STEP 2

1. Analyze the slope
2. Analyze the y-intercept
3. Summarize similarities and differences

STEP 3

Let's **investigate** the **slope** of y=2xy = 2x.
Remember, the general form of a linear equation is y=mx+by = mx + b, where mm is the **slope**.
In our case, m=2m = 2.
This tells us that for every **1 unit increase** in xx, yy increases by **2 units**.
It's a **positive slope**, so the line goes up as we move from left to right!

STEP 4

Now, let's **peek** at the **slope** of y=2x7y = 2x - 7.
Here, mm is *also* **2**!
So, for every **1 unit increase** in xx, yy *also* increases by **2 units**.

STEP 5

The **y-intercept** is the value of yy when x=0x = 0.
For y=2xy = 2x, if we plug in x=0x = 0, we get y=20=0y = 2 \cdot 0 = 0.
So, the **y-intercept** is **0**, meaning the line crosses the y-axis at the **origin** (0,0)(0, 0).

STEP 6

For y=2x7y = 2x - 7, if we plug in x=0x = 0, we get y=207=7y = 2 \cdot 0 - 7 = -7.
So, the **y-intercept** is **-7**.
This line crosses the y-axis at the point (0,7)(0, -7).

STEP 7

**Similarities**: Both lines have the *same* **slope** of 22, meaning they have the same **steepness** and are **parallel** to each other.

STEP 8

**Differences**: The lines have *different* **y-intercepts**.
The first line crosses the y-axis at y=0y = 0, while the second line crosses at y=7y = -7.
This means the second line is shifted **7 units down** compared to the first line.

STEP 9

Both lines have the same slope of 22 making them parallel, but they have different y-intercepts: 00 for y=2xy=2x and 7-7 for y=2x7y=2x-7.
This means y=2x7y=2x-7 is shifted 77 units down from y=2xy=2x.

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