Math  /  Trigonometry

QuestionDetermine the exact value of cot5π3\cot \frac{5 \pi}{3}.

Studdy Solution

STEP 1

What is this asking? We need to find the *exact* value of cotangent of 5π3\frac{5\pi}{3} radians, which means we want a nice, clean fraction, not a decimal approximation! Watch out! Remember cotangent is the reciprocal of tangent, not cosine!
Also, be careful with the signs in the different quadrants.

STEP 2

1. Relate Cotangent to Tangent
2. Find the Reference Angle
3. Evaluate the Tangent
4. Flip for Cotangent

STEP 3

Alright, let's **start** by remembering that cotangent is the reciprocal of tangent.
So, we can write: cot5π3=1tan5π3 \cot \frac{5\pi}{3} = \frac{1}{\tan \frac{5\pi}{3}} This means if we find tan5π3\tan \frac{5\pi}{3}, we just flip it over to get our answer!

STEP 4

Now, 5π3\frac{5\pi}{3} is in the **fourth quadrant**.
We know this because 5π3\frac{5\pi}{3} is between 3π2\frac{3\pi}{2} and 2π2\pi.

STEP 5

To find the **reference angle**, let's think about how far 5π3\frac{5\pi}{3} is from the x-axis.
In the fourth quadrant, we subtract our angle from 2π2\pi: 2π5π3=6π35π3=π3 2\pi - \frac{5\pi}{3} = \frac{6\pi}{3} - \frac{5\pi}{3} = \frac{\pi}{3} So, our **reference angle** is π3\frac{\pi}{3}!

STEP 6

We know that tanπ3=3\tan \frac{\pi}{3} = \sqrt{3}.
But remember, we're in the **fourth quadrant**, where tangent is negative.
So: tan5π3=3 \tan \frac{5\pi}{3} = -\sqrt{3}

STEP 7

Almost there!
Now we just need to take the reciprocal of our tangent value to find the cotangent: cot5π3=1tan5π3=13 \cot \frac{5\pi}{3} = \frac{1}{\tan \frac{5\pi}{3}} = \frac{1}{-\sqrt{3}}

STEP 8

Let's **rationalize the denominator** by multiplying the numerator and denominator by 3\sqrt{3}: 1333=33=33 \frac{1}{-\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{3}}{-3} = -\frac{\sqrt{3}}{3} And there we have it!

STEP 9

The exact value of cot5π3\cot \frac{5\pi}{3} is 33-\frac{\sqrt{3}}{3}.

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