Math  /  Numbers & Operations

QuestionDetermine the number of grams found in 3.2 mol of Li2 S\mathrm{Li}_{2} \mathrm{~S}. Hint: You must first calculate the molar mass of the compound. 45.95 g 45.953.2 g\frac{45.95}{3.2} \mathrm{~g} 3.245.95 g\frac{3.2}{45.95} \mathrm{~g} 3.245.95 g3.2 \cdot 45.95 \mathrm{~g}

Studdy Solution

STEP 1

1. We need to calculate the molar mass of the compound Li2 S\mathrm{Li}_{2} \mathrm{~S}.
2. The atomic masses are approximately: Li=6.94g/mol\mathrm{Li} = 6.94 \, \text{g/mol} and S=32.07g/mol\mathrm{S} = 32.07 \, \text{g/mol}.
3. We need to find the number of grams in 3.2mol3.2 \, \text{mol} of Li2 S\mathrm{Li}_{2} \mathrm{~S}.

STEP 2

1. Calculate the molar mass of Li2 S\mathrm{Li}_{2} \mathrm{~S}.
2. Use the molar mass to find the mass of 3.2mol3.2 \, \text{mol} of Li2 S\mathrm{Li}_{2} \mathrm{~S}.

STEP 3

Calculate the molar mass of Li2 S\mathrm{Li}_{2} \mathrm{~S}.
Molar mass of Li2 S=2×Molar mass of Li+Molar mass of S\text{Molar mass of } \mathrm{Li}_{2} \mathrm{~S} = 2 \times \text{Molar mass of } \mathrm{Li} + \text{Molar mass of } \mathrm{S}

STEP 4

Substitute the atomic masses into the equation.
Molar mass of Li2 S=2×6.94g/mol+32.07g/mol\text{Molar mass of } \mathrm{Li}_{2} \mathrm{~S} = 2 \times 6.94 \, \text{g/mol} + 32.07 \, \text{g/mol}

STEP 5

Calculate the total molar mass.
Molar mass of Li2 S=13.88g/mol+32.07g/mol=45.95g/mol\text{Molar mass of } \mathrm{Li}_{2} \mathrm{~S} = 13.88 \, \text{g/mol} + 32.07 \, \text{g/mol} = 45.95 \, \text{g/mol}

STEP 6

Use the molar mass to find the mass of 3.2mol3.2 \, \text{mol} of Li2 S\mathrm{Li}_{2} \mathrm{~S}.
Mass=Moles×Molar mass\text{Mass} = \text{Moles} \times \text{Molar mass}

STEP 7

Substitute the given values into the equation.
Mass=3.2mol×45.95g/mol\text{Mass} = 3.2 \, \text{mol} \times 45.95 \, \text{g/mol}

STEP 8

Calculate the mass.
Mass=147.04g\text{Mass} = 147.04 \, \text{g}
The number of grams found in 3.2mol3.2 \, \text{mol} of Li2 S\mathrm{Li}_{2} \mathrm{~S} is:
147.04g\boxed{147.04 \, \text{g}}

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