Math

Question Determine the truth value of pqp \vee q, where p:6+5=11p: 6+5=11 and q:7×3=42q: 7 \times 3=42. Choose the correct truth value: pqp \vee q is true or pqp \vee q is false.

Studdy Solution

STEP 1

Assumptions1. The statement pp is 6+5=116+5=11 . The statement qq is 7×3=427 \times3=42
3. The symbol \vee represents the logical OR operator. The statement pqp \vee q is true if either pp is true, or qq is true, or both are true.

STEP 2

First, we need to determine the truth value of the statement pp.
p6+5=11p6+5=11

STEP 3

Calculate the sum on the left side of the equation.
6+5=116+5=11

STEP 4

The sum of6 and is11, so the statement pp is true.

STEP 5

Next, we need to determine the truth value of the statement qq.
q7×3=42q7 \times3=42

STEP 6

Calculate the product on the left side of the equation.
×3=42 \times3=42

STEP 7

The product of7 and3 is21, not42, so the statement qq is false.

STEP 8

Now that we have the truth values for pp and qq, we can determine the truth value for the statement pqp \vee q.
pq=truefalsep \vee q = true \vee false

STEP 9

According to the rules of the logical OR operator, the statement pqp \vee q is true if either pp is true, or qq is true, or both are true. In this case, pp is true and qq is false, so pqp \vee q is true.
The statement pqp \vee q is true.

Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord