Math  /  Algebra

QuestionDetermine the value of yy, if xx is 2 . y=x2+5y=x^{2}+5

Studdy Solution

STEP 1

What is this asking? If yy is calculated by squaring xx and adding 5, what's yy when xx is 2? Watch out! Make sure to square xx *before* adding 5!
Order of operations is key!

STEP 2

1. Substitute
2. Calculate

STEP 3

Alright, so we're given the formula y=x2+5y = x^2 + 5.
We also know that x=2x = 2.
Let's **plug in** that value of xx into our formula for yy.
This is called **substitution**!

STEP 4

When we substitute x=2x = 2 into y=x2+5y = x^2 + 5, we get y=(2)2+5y = (2)^2 + 5.
See how we **replaced** xx with 2\textbf{2}?
Awesome!

STEP 5

Now, let's **calculate**!
First, we need to deal with that exponent.
Remember, 222^2 means 22 multiplied by itself: 22=42 \cdot 2 = \textbf{4}.

STEP 6

So, our equation becomes y=4+5y = \textbf{4} + 5.
We just replaced 222^2 with its value, which is **4**.

STEP 7

Finally, we add **4** and **5** together. 4+5=94 + 5 = \textbf{9}.
Therefore, y=9y = \textbf{9}!

STEP 8

When x=2x = 2, the value of yy is **9**.

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