Math  /  Geometry

QuestionDetermine which pairs of triangles are similar. Use a sketch to help explain how you know. \begin{tabular}{|l|l|l|} \hline \multicolumn{1}{|c|}{ Triangle } & \multicolumn{1}{|c|}{ Angles } & \multicolumn{1}{c|}{ Sides } \\ \hlineABC\triangle \mathrm{ABC} & A=90\angle \mathrm{A}=90^{\circ} & AB=6\mathrm{AB}=6 \\ &  B=45\angle \mathrm{~B}=45^{\circ} & BC=8.4\mathrm{BC}=8.4 \\ & C=45\angle \mathrm{C}=45^{\circ} & AC=6\mathrm{AC}=6 \\ \hlineEFG\triangle \mathrm{EFG} & E=90\angle \mathrm{E}=90^{\circ} & EF=3\mathrm{EF}=3 \\ &  F=45\angle \mathrm{~F}=45^{\circ} & FG=4.2\mathrm{FG}=4.2 \\ & G=45\angle \mathrm{G}=45^{\circ} & EG=3\mathrm{EG}=3 \\ \hlineHIJ\triangle \mathrm{HIJ} & H=90\angle \mathrm{H}=90^{\circ} & HI=9.2\mathrm{HI}=9.2 \\ & I=60\angle \mathrm{I}=60^{\circ} & IJ=18.4\mathrm{IJ}=18.4 \\ &  J=30\angle \mathrm{~J}=30^{\circ} & HJ=15.9\mathrm{HJ}=15.9 \\ \hlineKLM\triangle \mathrm{KLM} & K=90\angle \mathrm{K}=90^{\circ} & KL=9\mathrm{KL}=9 \\ &  L=45\angle \mathrm{~L}=45^{\circ} & LM=12.6\mathrm{LM}=12.6 \\ & M=45\angle \mathrm{M}=45^{\circ} & KM=9\mathrm{KM}=9 \\ \hline \end{tabular}

Studdy Solution

STEP 1

What is this asking? Which of these triangles are like twins, but maybe different sizes? Watch out! Just because two triangles look similar, doesn't mean they are!
We need to check if their angles match and their sides are proportional.

STEP 2

1. Check for Similar Triangles using Angle-Angle Similarity
2. Check for Similar Triangles using Side-Side-Side Similarity

STEP 3

Let's **look** at the angles!
If two triangles have two matching angles, they're similar!
This is called Angle-Angle similarity.

STEP 4

Triangles ABC\triangle ABC, EFG\triangle EFG, and KLM\triangle KLM all have angles of 9090^\circ, 4545^\circ, and 4545^\circ.
Boom! They're similar! HIJ\triangle HIJ has different angles, so it's not similar to the others.

STEP 5

Even though we know ABC\triangle ABC, EFG\triangle EFG, and KLM\triangle KLM are similar because of their angles, let's check if their sides are proportional too!
This is called Side-Side-Side similarity.

STEP 6

For ABC\triangle ABC and EFG\triangle EFG, let's see.
We have: ABEF=63=2\frac{AB}{EF} = \frac{6}{3} = \textbf{2} BCFG=8.44.2=2\frac{BC}{FG} = \frac{8.4}{4.2} = \textbf{2}ACEG=63=2\frac{AC}{EG} = \frac{6}{3} = \textbf{2}All the ratios are **2**!
That means the sides are proportional!

STEP 7

Now, let's compare ABC\triangle ABC and KLM\triangle KLM: ABKL=69=23\frac{AB}{KL} = \frac{6}{9} = \frac{2}{3} BCLM=8.412.6=23\frac{BC}{LM} = \frac{8.4}{12.6} = \frac{2}{3}ACKM=69=23\frac{AC}{KM} = \frac{6}{9} = \frac{2}{3}Again, all the ratios are the same, this time 23\frac{\textbf{2}}{\textbf{3}}!
So, these triangles are also similar!

STEP 8

Finally, let's compare EFG\triangle EFG and KLM\triangle KLM: EFKL=39=13\frac{EF}{KL} = \frac{3}{9} = \frac{1}{3} FGLM=4.212.6=13\frac{FG}{LM} = \frac{4.2}{12.6} = \frac{1}{3}EGKM=39=13\frac{EG}{KM} = \frac{3}{9} = \frac{1}{3}All ratios are 13\frac{\textbf{1}}{\textbf{3}}, confirming they're similar!

STEP 9

ABC\triangle ABC, EFG\triangle EFG, and KLM\triangle KLM are all similar to each other. HIJ\triangle HIJ is not similar to any of the other triangles.

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