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Math

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PROBLEM

Compare the sums O=3+5+7++103O = 3 + 5 + 7 + \ldots + 103 and E=4+6+8++104E = 4 + 6 + 8 + \ldots + 104. Which is greater and by how much?

STEP 1

Assumptions1. The series O represents the sum of odd numbers from3 to103.
. The series represents the sum of even numbers from4 to104.
3. Both series are arithmetic series, with a common difference of.

STEP 2

First, we need to find the number of terms in each series. The formula to find the number of terms in an arithmetic series isn=LasttermFirsttermCommondifference+1n = \frac{Last\, term - First\, term}{Common\, difference} +1

STEP 3

Calculate the number of terms in series O.
n=10332+1n = \frac{103 -3}{2} +1

STEP 4

Calculate the number of terms in series.
nE=10442+1n_E = \frac{104 -4}{2} +1

STEP 5

The sum of an arithmetic series can be found using the formulaSum=n2×(Firstterm+Lastterm)Sum = \frac{n}{2} \times (First\, term + Last\, term)

STEP 6

Calculate the sum of series O without actually computing the sum.
=n2×(3+103) = \frac{n}{2} \times (3 +103)

STEP 7

Calculate the sum of series without actually computing the sum.
=nE2×(4+104) = \frac{n_E}{2} \times (4 +104)

STEP 8

Now, we need to find which series has a greater sum and by how much. We can do this by subtracting the smaller sum from the larger sum.
If > >, then Difference=ODifference = O -
If >O > O, then Difference=ODifference = - O

SOLUTION

Finally, simplify the difference to find which series has a greater sum and by how much.

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