Math

QuestionDiberikan M=K+LTM=K+L^{\mathrm{T}}, cari nilai yy yang memenuhi dengan K=(5x+12yx)K=\begin{pmatrix}5 & x+1 \\ 2 & y-x\end{pmatrix} dan L=(452x13x+y)L=\begin{pmatrix}4 & 5 \\ 2x-1 & 3x+y\end{pmatrix}. Pilihan: a. -4, b. -3, c. -2, d. 3, e. 4.

Studdy Solution

STEP 1

Assumptions1. We have matrix K=(5x+1yx)K=\left(\begin{array}{ll}5 & x+1 \\ & y-x\end{array}\right). We have matrix =(45x13x+y)=\left(\begin{array}{cc}4 &5 \\ x-1 &3 x+y\end{array}\right)3. We have matrix M=(9127)M=\left(\begin{array}{cc}9 &12 \\7 &\end{array}\right)4. We know that M=K+TM=K+^{\mathrm{T}}, where T^{\mathrm{T}} is the transpose of matrix $$
5. We need to find the value of $y$ that satisfies the equation $M=K+^{\mathrm{T}}$

STEP 2

First, we need to find the transpose of matrix $$. The transpose of a matrix is obtained by interchanging its rows into columns or vice versa.
T=(42x15x+y)^{\mathrm{T}} = \left(\begin{array}{cc}4 &2 x-1 \\5 & x+y\end{array}\right)

STEP 3

Now, we can add matrix KK and T^{\mathrm{T}} to get matrix MM.
M=K+LTM = K + L^{\mathrm{T}}(91272)=(5x+12yx)+(2x153x+y)\left(\begin{array}{cc}9 &12 \\7 &2\end{array}\right) = \left(\begin{array}{ll}5 & x+1 \\2 & y-x\end{array}\right) + \left(\begin{array}{cc} &2 x-1 \\5 &3 x+y\end{array}\right)

STEP 4

We can equate the corresponding elements of the matrices on both sides of the equation.
+4=9,x+1+2x1=12,2+=7,yx+3x+y=2 +4 =9, x+1 +2x-1 =12,2 + =7, y-x +3x+y =2

STEP 5

olving the equations, we getx=3,y=2x =3, y = -2So, the value of yy that satisfies the equation is -2.

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