QuestionDivide or multiply these measurements, ensuring correct significant digits:
213.30 mol ÷ 85.1 L = $\square$ mol/L 7.808 mol/L × 3.1 L = $\square$ mol 248.6 mol ÷ 0.46 L = $\square$ mol/L

Studdy Solution

STEP 1

Assumptions1. We are given three problems to solve, each involving multiplication or division of measurements. . The measurements are in moles (mol) and liters ().
3. We need to ensure that our answers contain the correct number of significant digits.

STEP 2

Let's start with the first problem. We need to divide213.30 mol by85.1 L.
$\frac{213.30\, mol}{85.1\, L}$

STEP 3

Perform the division.
$\frac{213.30\, mol}{85.1\, L} =2.505 mol/L$

STEP 4

Now, we need to ensure that our answer has the correct number of significant digits. The rule for division is that the answer should have the same number of significant digits as the number with the least significant digits in the problem. In this case,85.1 L has three significant digits. So, our answer should also have three significant digits.
$2.505 mol/L \approx2.51 mol/L$

STEP 5

Next, let's move on to the second problem. We need to multiply7.808 mol/L by3.1 L.
$7.808\, mol/L \times3.1\, L$

STEP 6

Perform the multiplication.
$.808\, mol/L \times3.1\, L =24.2048\, mol$

STEP 7

Again, we need to ensure that our answer has the correct number of significant digits. The rule for multiplication is the same as for division. In this case,3.1 L has two significant digits. So, our answer should also have two significant digits.
$24.204\, mol \approx24\, mol$

STEP 8

Finally, let's solve the third problem. We need to divide248.6 mol by0.46 L.
$\frac{248.6\, mol}{0.46\, L}$

STEP 9

Perform the division.
$\frac{248.6\, mol}{.46\, L} =540.4347826087\, mol/L$

STEP 10

Once more, we need to ensure that our answer has the correct number of significant digits. In this case,0.46 L has two significant digits. So, our answer should also have two significant digits.
$540.4347826087\, mol/L \approx540\, mol/L$ So, the solutions to the problems are. $213.30\, mol \div85.\, L =2.51\, mol/L$ 2. $7.808\, mol/L \times3.\, L =24\, mol$ 3. $248.6\, mol \div0.46\, L =540\, mol/L$

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QuestionDivide or multiply these measurements, ensuring correct significant digits:
213.30 mol ÷ 85.1 L = $\square$ mol/L 7.808 mol/L × 3.1 L = $\square$ mol 248.6 mol ÷ 0.46 L = $\square$ mol/L

Studdy Solution

STEP 1

Assumptions1. We are given three problems to solve, each involving multiplication or division of measurements. . The measurements are in moles (mol) and liters ().
3. We need to ensure that our answers contain the correct number of significant digits.

STEP 2

Let's start with the first problem. We need to divide213.30 mol by85.1 L.
$\frac{213.30\, mol}{85.1\, L}$

STEP 3

Perform the division.
$\frac{213.30\, mol}{85.1\, L} =2.505 mol/L$

STEP 4

STEP 5

Next, let's move on to the second problem. We need to multiply7.808 mol/L by3.1 L.
$7.808\, mol/L \times3.1\, L$

STEP 6

Perform the multiplication.
$.808\, mol/L \times3.1\, L =24.2048\, mol$

STEP 7

Again, we need to ensure that our answer has the correct number of significant digits. The rule for multiplication is the same as for division. In this case,3.1 L has two significant digits. So, our answer should also have two significant digits.
$24.204\, mol \approx24\, mol$

STEP 8

Finally, let's solve the third problem. We need to divide248.6 mol by0.46 L.
$\frac{248.6\, mol}{0.46\, L}$

STEP 9

Perform the division.
$\frac{248.6\, mol}{.46\, L} =540.4347826087\, mol/L$

STEP 10

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QuestionDivide or multiply these measurements, ensuring correct significant digits: 213.30 mol ÷ 85.1 L = □\square□ mol/L 7.808 mol/L × 3.1 L = □\square□ mol 248.6 mol ÷ 0.46 L = □\square□ mol/L

Studdy Solution

STEP 1

Assumptions1. We are given three problems to solve, each involving multiplication or division of measurements. . The measurements are in moles (mol) and liters ().3. We need to ensure that our answers contain the correct number of significant digits.

STEP 2

Let's start with the first problem. We need to divide213.30 mol by85.1 L.213.30 mol85.1 L\frac{213.30\, mol}{85.1\, L}85.1L213.30mol​

STEP 3

Perform the division.213.30 mol85.1 L=2.505mol/L\frac{213.30\, mol}{85.1\, L} =2.505 mol/L85.1L213.30mol​=2.505mol/L

STEP 4

STEP 5

Next, let's move on to the second problem. We need to multiply7.808 mol/L by3.1 L.7.808 mol/L×3.1 L7.808\, mol/L \times3.1\, L7.808mol/L×3.1L

STEP 6

Perform the multiplication..808 mol/L×3.1 L=24.2048 mol.808\, mol/L \times3.1\, L =24.2048\, mol.808mol/L×3.1L=24.2048mol

STEP 7

STEP 8

Finally, let's solve the third problem. We need to divide248.6 mol by0.46 L.248.6 mol0.46 L\frac{248.6\, mol}{0.46\, L}0.46L248.6mol​

STEP 9

Perform the division.248.6 mol.46 L=540.4347826087 mol/L\frac{248.6\, mol}{.46\, L} =540.4347826087\, mol/L.46L248.6mol​=540.4347826087mol/L

STEP 10

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QuestionDivide or multiply these measurements, ensuring correct significant digits:
213.30 mol ÷ 85.1 L = $\square$ mol/L 7.808 mol/L × 3.1 L = $\square$ mol 248.6 mol ÷ 0.46 L = $\square$ mol/L

Assumptions1. We are given three problems to solve, each involving multiplication or division of measurements. . The measurements are in moles (mol) and liters ().
3. We need to ensure that our answers contain the correct number of significant digits.

Let's start with the first problem. We need to divide213.30 mol by85.1 L.
$\frac{213.30\, mol}{85.1\, L}$

Perform the division.
$\frac{213.30\, mol}{85.1\, L} =2.505 mol/L$

Next, let's move on to the second problem. We need to multiply7.808 mol/L by3.1 L.
$7.808\, mol/L \times3.1\, L$

Perform the multiplication.
$.808\, mol/L \times3.1\, L =24.2048\, mol$

Finally, let's solve the third problem. We need to divide248.6 mol by0.46 L.
$\frac{248.6\, mol}{0.46\, L}$

Perform the division.
$\frac{248.6\, mol}{.46\, L} =540.4347826087\, mol/L$