Math  /  Algebra

QuestionDivide as indicated. Simplify the answer. ab5a+5b÷a2b2a2+4a+4ab5a+5b÷a2b2a2+4a+4=\begin{array}{r} \frac{a-b}{5 a+5 b} \div \frac{a^{2}-b^{2}}{a^{2}+4 a+4} \\ \frac{a-b}{5 a+5 b} \div \frac{a^{2}-b^{2}}{a^{2}+4 a+4}=\square \end{array} \square

Studdy Solution

STEP 1

1. The problem involves division of two rational expressions.
2. Simplification involves factoring polynomials and reducing common factors.
3. The expression is simplified by multiplying by the reciprocal.

STEP 2

1. Rewrite the division as multiplication by the reciprocal.
2. Factor the polynomials in the numerators and denominators.
3. Simplify by canceling common factors.

STEP 3

Rewrite the division of fractions as multiplication by the reciprocal:
ab5a+5b÷a2b2a2+4a+4=ab5a+5b×a2+4a+4a2b2\frac{a-b}{5a+5b} \div \frac{a^2-b^2}{a^2+4a+4} = \frac{a-b}{5a+5b} \times \frac{a^2+4a+4}{a^2-b^2}

STEP 4

Factor the polynomials:
- The denominator 5a+5b5a + 5b can be factored as 5(a+b)5(a + b). - The numerator a2b2a^2 - b^2 is a difference of squares and can be factored as (ab)(a+b)(a-b)(a+b). - The numerator a2+4a+4a^2 + 4a + 4 is a perfect square trinomial and can be factored as (a+2)2(a+2)^2.
The expression becomes:
ab5(a+b)×(a+2)2(ab)(a+b)\frac{a-b}{5(a+b)} \times \frac{(a+2)^2}{(a-b)(a+b)}

STEP 5

Simplify the expression by canceling common factors:
- Cancel aba-b from the numerator and denominator. - Cancel a+ba+b from the numerator and denominator.
The simplified expression is:
(a+2)25\frac{(a+2)^2}{5}
The simplified answer is:
(a+2)25\boxed{\frac{(a+2)^2}{5}}

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