Question Determine which lake - Jensen, Parlow, or Stockton - lost the least amount of water during a drought, where Jensen lost $\frac{4}{9}$ , Parlow lost $45\%$ , and Stockton lost $\frac{138}{300}$ of their water.

Studdy Solution

STEP 1

Assumptions1. Lake Jensen lost $\frac{4}{9}$ of its water. Lake Parlow lost $45\%$ of its water3. Lake Stockton lost $\frac{138}{300}$ of its water4. The comparison is based on the proportion of water lost, not the actual volume of water

STEP 2

First, we need to convert all the fractions and percentages to a common form for easy comparison. Let's convert everything to decimals.
For Lake Jensen, we have $\frac{4}{9} =0.444...$

STEP 3

For Lake Parlow, we need to convert the percentage to a decimal. We can do this by dividing the percentage by100.
$45\% = \frac{45}{100} =0.45$

STEP 4

For Lake Stockton, we have $\frac{138}{300} =0.46$

STEP 5

Now that we have all the fractions and percentages converted to decimals, we can easily compare them.
Lake Jensen lost $0.444...$ of its water, Lake Parlow lost $0.45$ of its water, and Lake Stockton lost $0.46$ of its water.

STEP 6

Comparing these values, we can see that Lake Jensen lost the least amount of water.
Lake Jensen lost the least amount of water.

Was this helpful?

Question Determine which lake - Jensen, Parlow, or Stockton - lost the least amount of water during a drought, where Jensen lost $\frac{4}{9}$ , Parlow lost $45\%$ , and Stockton lost $\frac{138}{300}$ of their water.

Studdy Solution

STEP 1

Assumptions1. Lake Jensen lost $\frac{4}{9}$ of its water. Lake Parlow lost $45\%$ of its water3. Lake Stockton lost $\frac{138}{300}$ of its water4. The comparison is based on the proportion of water lost, not the actual volume of water

STEP 2

First, we need to convert all the fractions and percentages to a common form for easy comparison. Let's convert everything to decimals.
For Lake Jensen, we have $\frac{4}{9} =0.444...$

STEP 3

For Lake Parlow, we need to convert the percentage to a decimal. We can do this by dividing the percentage by100.
$45\% = \frac{45}{100} =0.45$

STEP 4

For Lake Stockton, we have $\frac{138}{300} =0.46$

STEP 5

Now that we have all the fractions and percentages converted to decimals, we can easily compare them.
Lake Jensen lost $0.444...$ of its water, Lake Parlow lost $0.45$ of its water, and Lake Stockton lost $0.46$ of its water.

STEP 6

Comparing these values, we can see that Lake Jensen lost the least amount of water.
Lake Jensen lost the least amount of water.

Get Studdy

Studdy solves anything!

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

Question Determine which lake - Jensen, Parlow, or Stockton - lost the least amount of water during a drought, where Jensen lost 49\frac{4}{9}94​, Parlow lost 45%45\%45%, and Stockton lost 138300\frac{138}{300}300138​ of their water.

Studdy Solution

STEP 1

Assumptions1. Lake Jensen lost 49\frac{4}{9}94​ of its water. Lake Parlow lost 45%45\%45% of its water3. Lake Stockton lost 138300\frac{138}{300}300138​ of its water4. The comparison is based on the proportion of water lost, not the actual volume of water

STEP 2

First, we need to convert all the fractions and percentages to a common form for easy comparison. Let's convert everything to decimals.For Lake Jensen, we have49=0.444...\frac{4}{9} =0.444...94​=0.444...

STEP 3

For Lake Parlow, we need to convert the percentage to a decimal. We can do this by dividing the percentage by100.45%=45100=0.4545\% = \frac{45}{100} =0.4545%=10045​=0.45

STEP 4

For Lake Stockton, we have138300=0.46\frac{138}{300} =0.46300138​=0.46

STEP 5

Now that we have all the fractions and percentages converted to decimals, we can easily compare them.Lake Jensen lost 0.444...0.444...0.444... of its water, Lake Parlow lost 0.450.450.45 of its water, and Lake Stockton lost 0.460.460.46 of its water.

STEP 6

Comparing these values, we can see that Lake Jensen lost the least amount of water.Lake Jensen lost the least amount of water.

Get Studdy

Studdy solves anything!

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

Question Determine which lake - Jensen, Parlow, or Stockton - lost the least amount of water during a drought, where Jensen lost $\frac{4}{9}$ , Parlow lost $45\%$ , and Stockton lost $\frac{138}{300}$ of their water.

Assumptions1. Lake Jensen lost $\frac{4}{9}$ of its water. Lake Parlow lost $45\%$ of its water3. Lake Stockton lost $\frac{138}{300}$ of its water4. The comparison is based on the proportion of water lost, not the actual volume of water

First, we need to convert all the fractions and percentages to a common form for easy comparison. Let's convert everything to decimals.
For Lake Jensen, we have $\frac{4}{9} =0.444...$

For Lake Parlow, we need to convert the percentage to a decimal. We can do this by dividing the percentage by100.
$45\% = \frac{45}{100} =0.45$

For Lake Stockton, we have $\frac{138}{300} =0.46$

Now that we have all the fractions and percentages converted to decimals, we can easily compare them.
Lake Jensen lost $0.444...$ of its water, Lake Parlow lost $0.45$ of its water, and Lake Stockton lost $0.46$ of its water.

Comparing these values, we can see that Lake Jensen lost the least amount of water.
Lake Jensen lost the least amount of water.