Math

QuestionEvaluate the expression 62+10÷(5)(3)56^{2}+10 \div(-5)(3)-5 using order of operations. What to do first?

Studdy Solution

STEP 1

Assumptions1. The expression to be evaluated is 6+10÷(5)(3)56^{}+10 \div(-5)(3)-5 . The operations to be performed are exponentiation, division, multiplication, addition, and subtraction.
3. The order of operations is as follows parentheses, exponents, multiplication and division (from left to right), addition and subtraction (from left to right).

STEP 2

First, we need to evaluate the exponentiation operation, which is 626^{2}.
62=366^{2} =36

STEP 3

Next, we need to perform the division operation, which is 10÷(5)10 \div(-5).
10÷(5)=210 \div(-5) = -2

STEP 4

Now we need to perform the multiplication operation, which is 2(3)-2(3).
2(3)=6-2(3) = -6

STEP 5

Now we substitute these results back into the original expression.
36+()536 + (-) -5

STEP 6

Next, we perform the addition operation, which is 36+(6)36 + (-6).
36+(6)=3036 + (-6) =30

STEP 7

Finally, we perform the subtraction operation, which is 30530 -5.
305=2530 -5 =25So, the result of the expression 62+10÷(5)(3)56^{2}+10 \div(-5)(3)-5 is25.

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