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PROBLEM

Evaluate. Assume u>0u>0 when ln4\ln 4 appears
x11ex12dx\int x^{11} e^{x^{12}} d x

STEP 1

1. We are given the integral x11ex12dx\int x^{11} e^{x^{12}} \, dx.
2. We assume u>0u > 0 when ln4\ln 4 appears, although ln4\ln 4 does not directly appear in this problem.
3. We will use substitution to solve the integral.

STEP 2

1. Identify a substitution to simplify the integral.
2. Apply the substitution to the integral.
3. Simplify the integral in terms of the new variable.
4. Integrate with respect to the new variable.
5. Substitute back to the original variable.

STEP 3

Identify a substitution. Let:
u=x12 u = x^{12} Then, differentiate u u with respect to x x :
dudx=12x11 \frac{du}{dx} = 12x^{11}

STEP 4

Solve for dx dx in terms of du du and x x :
du=12x11dx du = 12x^{11} \, dx dx=112x11du dx = \frac{1}{12x^{11}} \, du

STEP 5

Substitute u=x12 u = x^{12} and dx=112x11du dx = \frac{1}{12x^{11}} \, du into the integral:
x11ex12dx=x11eu112x11du \int x^{11} e^{x^{12}} \, dx = \int x^{11} e^{u} \cdot \frac{1}{12x^{11}} \, du Simplify the expression:
=112eudu = \frac{1}{12} \int e^{u} \, du

STEP 6

Integrate with respect to u u :
112eudu=112eu+C \frac{1}{12} \int e^{u} \, du = \frac{1}{12} e^{u} + C where C C is the constant of integration.

SOLUTION

Substitute back u=x12 u = x^{12} into the integrated result:
112eu+C=112ex12+C \frac{1}{12} e^{u} + C = \frac{1}{12} e^{x^{12}} + C The evaluated integral is:
112ex12+C \boxed{\frac{1}{12} e^{x^{12}} + C}

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