QuestionEvaluate $E(82)$ where $E(82)=\sqrt{4(82)+33}$ .

Studdy Solution

STEP 1

Assumptions1. The function(x) is defined as $(x)=\sqrt{4x+33}$

STEP 2

We need to evaluate the function(x) at x=82. We can do this by substituting x=82 into the function.
$(82)=\sqrt{4(82)+33}$

STEP 3

First, we need to calculate the value inside the square root. This can be done by multiplying by82 and then adding33.
$(82)+33 =328 +33 =361$

STEP 4

Substitute this value back into the function.
$(82)=\sqrt{361}$

STEP 5

Evaluate the square root of361.
$(82)=\sqrt{361} =19$ So, $(82) =19$ .

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QuestionEvaluate $E(82)$ where $E(82)=\sqrt{4(82)+33}$ .

Studdy Solution

STEP 1

Assumptions1. The function(x) is defined as $(x)=\sqrt{4x+33}$

STEP 2

We need to evaluate the function(x) at x=82. We can do this by substituting x=82 into the function.
$(82)=\sqrt{4(82)+33}$

STEP 3

First, we need to calculate the value inside the square root. This can be done by multiplying by82 and then adding33.
$(82)+33 =328 +33 =361$

STEP 4

Substitute this value back into the function.
$(82)=\sqrt{361}$

STEP 5

Evaluate the square root of361.
$(82)=\sqrt{361} =19$ So, $(82) =19$ .

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QuestionEvaluate E(82)E(82)E(82) where E(82)=4(82)+33E(82)=\sqrt{4(82)+33}E(82)=4(82)+33​.

Studdy Solution

STEP 1

Assumptions1. The function(x) is defined as (x)=4x+33(x)=\sqrt{4x+33}(x)=4x+33​

STEP 2

We need to evaluate the function(x) at x=82. We can do this by substituting x=82 into the function.(82)=4(82)+33(82)=\sqrt{4(82)+33}(82)=4(82)+33​

STEP 3

First, we need to calculate the value inside the square root. This can be done by multiplying by82 and then adding33.(82)+33=328+33=361(82)+33 =328 +33 =361(82)+33=328+33=361

STEP 4

Substitute this value back into the function.(82)=361(82)=\sqrt{361}(82)=361​

STEP 5

Evaluate the square root of361.(82)=361=19(82)=\sqrt{361} =19(82)=361​=19So, (82)=19(82) =19(82)=19.

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QuestionEvaluate $E(82)$ where $E(82)=\sqrt{4(82)+33}$ .

Assumptions1. The function(x) is defined as $(x)=\sqrt{4x+33}$

We need to evaluate the function(x) at x=82. We can do this by substituting x=82 into the function.
$(82)=\sqrt{4(82)+33}$

First, we need to calculate the value inside the square root. This can be done by multiplying by82 and then adding33.
$(82)+33 =328 +33 =361$

Substitute this value back into the function.
$(82)=\sqrt{361}$

Evaluate the square root of361.
$(82)=\sqrt{361} =19$ So, $(82) =19$ .