Solve a problem of your own!
Download the Studdy App!

Math

Math Snap

PROBLEM

Find (fg)(x)(f \circ g)(x) and its domain in interval notation, where f(x)=xx1f(x)=\frac{x}{x-1} and g(x)=13x236g(x)=\frac{13}{x^{2}-36}.

STEP 1

Assumptions1. The function f(x)f(x) is given by f(x)=xx1f(x)=\frac{x}{x-1}
. The function g(x)g(x) is given by g(x)=13x36g(x)=\frac{13}{x^{}-36}
3. We are asked to find the composition of the functions ff and gg, denoted as (fg)(x)(f \circ g)(x)

STEP 2

The composition of two functions, ff and gg, is defined as (fg)(x)=f(g(x))(f \circ g)(x) = f(g(x)). This means that we substitute the function g(x)g(x) into the function f(x)f(x).

STEP 3

Substitute g(x)g(x) into f(x)f(x) to get the composition of the functions.
(fg)(x)=f(g(x))=g(x)g(x)1(f \circ g)(x) = f(g(x)) = \frac{g(x)}{g(x)-1}

STEP 4

Now, substitute the given function g(x)g(x) into the expression.
(fg)(x)=13x23613x2361(f \circ g)(x) = \frac{\frac{13}{x^{2}-36}}{\frac{13}{x^{2}-36}-1}

STEP 5

To simplify this expression, we can multiply the numerator and the denominator by x236x^{2}-36 to get rid of the complex fraction.
(fg)(x)=1313x236(x236)(x236)(f \circ g)(x) = \frac{13}{\frac{13}{x^{2}-36} \cdot (x^{2}-36) - (x^{2}-36)}

STEP 6

implify the denominator.
(fg)(x)=1313x2+36(f \circ g)(x) = \frac{13}{13 - x^{2} +36}

SOLUTION

implify the expression further.
(fg)(x)=1349x2(f \circ g)(x) = \frac{13}{49 - x^{2}}This is the composition of the functions ff and gg, (fg)(x)(f \circ g)(x).

Was this helpful?
banner

Start understanding anything

Get started now for free.

OverviewParentsContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord