Math

Question Simplify the expressions: (a) eln(7)e^{\ln (\sqrt{7})}, (b) eln(1/π)e^{\ln (1 / \pi)}, (c) 10log(15)10^{\log (15)}.

Studdy Solution

STEP 1

Assumptions
1. We are dealing with exponential and logarithmic functions.
2. The base of the natural logarithm ln\ln is ee.
3. The properties of logarithms and exponents will be used to simplify the expressions.
4. The base of the common logarithm log\log is 1010.

STEP 2

Evaluate the expression eln(7)e^{\ln (\sqrt{7})}.
We will use the property that elnx=xe^{\ln x} = x for any positive number xx.

STEP 3

Recognize that 7\sqrt{7} is a positive number, so we can apply the property directly.
eln(7)=7e^{\ln (\sqrt{7})} = \sqrt{7}

STEP 4

The expression simplifies to:
eln(7)=7e^{\ln (\sqrt{7})} = \sqrt{7}

STEP 5

Evaluate the expression eln(1/π)e^{\ln (1 / \pi)}.
Again, we will use the property that elnx=xe^{\ln x} = x for any positive number xx.

STEP 6

Recognize that 1/π1 / \pi is a positive number, so we can apply the property directly.
eln(1/π)=1πe^{\ln (1 / \pi)} = \frac{1}{\pi}

STEP 7

The expression simplifies to:
eln(1/π)=1πe^{\ln (1 / \pi)} = \frac{1}{\pi}

STEP 8

Evaluate the expression 10log(15)10^{\log (15)}.
We will use the property that 10logx=x10^{\log x} = x for any positive number xx.

STEP 9

Recognize that 1515 is a positive number, so we can apply the property directly.
10log(15)=1510^{\log (15)} = 15

STEP 10

The expression simplifies to:
10log(15)=1510^{\log (15)} = 15
Solutions: (a) eln(7)=7e^{\ln (\sqrt{7})} = \sqrt{7} (b) eln(1/π)=1πe^{\ln (1 / \pi)} = \frac{1}{\pi} (c) 10log(15)=1510^{\log (15)} = 15

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